thực hiện phép tính :\(\frac{4^{1007}\cdot9^{1007}}{3^{2015}\cdot16^{503}}\)
giúp mình nhanh lên nhé
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\(\frac{4^{1007}.9^{1007}}{3^{2015}.16^{503}}=\frac{4^{1007}.\left(3^2\right)^{1007}}{3^{2015}.\left(4^2\right)^{503}}=\frac{4^{1007}.3^{2014}}{3^{2015}.4^{1006}}=\frac{4}{3}\)
\(\frac{4^{1007}.9^{1007}}{3^{2015}.2^{2016}}=\frac{\left(2^2\right)^{1007}.\left(3^2\right)^{1007}}{3^{2015}.2^{2016}}\)
\(=\frac{2^{2014}.3^{2014}}{3^{2015}.2^{2016}}=\frac{2^{2014}.3^{2014}}{3^{2014}.2^{2014}.3.2^2}\)
\(=\frac{1}{3.2^2}=\frac{1}{3.4}=\frac{1}{12}\)
Rút gọn
\(\frac{4^{1007}\cdot9^{1007}}{3^{2015}\cdot2^{2016}}=\frac{\left(2^2\right)^{2007}\cdot\left(3^2\right)^{1007}}{3^{2015}\cdot2^{2016}}\)
\(=\frac{2^{2\cdot1007}\cdot3^{2\cdot1007}}{3^{2015}\cdot2^{2016}}=\frac{2^{2014}\cdot3^{2014}}{3^{2015}\cdot2^{2016}}\)
\(=\frac{1}{3.2^2}=\frac{1}{12}\)
Vậy ...
hok tót .
\(\frac{4^{1007}.9^{1007}}{3^{2015}.16^{503}}=\frac{4^{1007}.\left(3^2\right)^{1007}}{3^{2015}.\left(4^2\right)^{503}}=\frac{4^{1007}.3^{2014}}{3^{2015}.4^{1006}}=\frac{4}{3}\)
\(\frac{4^{1007}.9^{1007}}{3^{2015}.16^{503}}=\frac{4^{1007}.\left(3^2\right)^{1007}}{3^{2015}.\left(4^2\right)^{503}}=\frac{4^{1007}.3^{2014}}{3^{2015}.4^{1006}}=\frac{4}{3}\)
Cho hỏi viết số mũ như thế nào vậy Chỉ cho mk với
\(\frac{4^{1007}\cdot9^{1007}}{3^{2015}\cdot16^{503}}\)
\(=\frac{\left(2^2\right)^{1007}\cdot\left(3^2\right)^{1007}}{3^{2015}\cdot\left(2^4\right)^{503}}\)
\(=\frac{2^{2014}\cdot3^{2014}}{3^{2015}\cdot2^{2012}}\)
\(=\frac{2^2\cdot1}{3\cdot1}=\frac{4}{3}\)