f) 6.7.168 – 14.85.3 + 17.21.2
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(=\left(6.7\right).16-\left(14.3\right).85+17.\left(21.2\right)\)
\(=42.16-42.85+17.42\)
\(=42.\left(16-85+42\right)\)
\(=42.\left(-27\right)\)
\(=-1134\)
( ko bt sai hay đúng )
~HT~
1.
y=f(-1)=3*(-1)-2=-5
y=f(0)=3*0-2=-2
y=f(-2)=3*(-2)-2=-8
y=f(3)=3*3-2=7
Câu 2,3a làm tương tự,chỉ việc thay f(x) thôi.
3b
Khi y=5 =>5=5-2*x=>2*x=0=> x=0
Khi y=3=>3=5-2*x=>2*x=2=>x=1
Khi y=-1=>-1=5-2*x=>2*x=6=>x=3
f(-1)=3.1-2=3-2=1
f(0)=3.0-2=0-2=-2
f(-2)=3.(-2)-2=-6-2=-8
f(3)=3.3-2=9-2=7
\(f\left(-x\right)=100-\left(-x\right)^2=100-x^2=f\left(x\right)\)
\(f\left(-3\right)=\left(-3\right)^2+1=9+1=10\)
\(f\left(-1\right)=\left(-1\right)^2+1=1+1=2\)
\(f\left(3\right)=3^2+1=9+1=10\)
\(f\left(0\right)=0^2+1=1\)
\(f\left(-\dfrac{1}{2}\right)=\left(-\dfrac{1}{2}\right)^2+1=\dfrac{1}{4}+\dfrac{4}{4}=\dfrac{5}{4}\)
\(f\left(\dfrac{1}{2}\right)=\left(\dfrac{1}{2}\right)^2+1=\dfrac{1}{4}+\dfrac{4}{4}=\dfrac{5}{4}\)
\(f\left(\dfrac{2}{3}\right)=\left(\dfrac{2}{3}\right)^2+1=\dfrac{4}{9}+\dfrac{9}{9}=\dfrac{13}{9}\)
\(f\left(-\dfrac{2}{3}\right)=\left(-\dfrac{2}{3}\right)^2+1=\dfrac{4}{9}+\dfrac{9}{9}=\dfrac{13}{9}\)
6.7.168 – 14.85.3 + 17.21.2
= 42 . 168 - 42 . 85 + 42 . 17
= 42 . ( 168 - 85 + 17 )
= 42 . 100
= 4200
= 2.3.7.168 - 2.7.85.3 + 17.2.21
= 21.336 - 21.170 + 21.34
= 21.( 336 + 34 - 170 )
= 21.200
= 4200