50-50:[3.(2^3-4)+13]
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\(a,=\dfrac{13}{50}\cdot\dfrac{50}{13}\cdot\left(-\dfrac{31}{2}\right)\cdot\dfrac{169}{2}=-\dfrac{5239}{2}\\ b,=\dfrac{-\dfrac{49}{100}\cdot\left(-125\right)}{-\dfrac{343}{27}\cdot\dfrac{81}{16}\cdot\left(-1\right)}=\dfrac{\dfrac{245}{4}}{\dfrac{1029}{16}}=\dfrac{245}{4}\cdot\dfrac{16}{1029}=\dfrac{20}{21}\)
a) \(\dfrac{13}{50}.\left(-15.5\right):\dfrac{13}{50}.84\dfrac{1}{2}=\dfrac{13}{50}.-75:\dfrac{13}{50}.\dfrac{169}{2}=-\dfrac{75.169}{2}=-\dfrac{12675}{2}\)
b) \(\dfrac{\left(-0,7\right)^2.\left(-5\right)^3}{\left(-2\dfrac{1}{3}\right)^3.\left(1\dfrac{1}{2}\right)^4.\left(-1\right)^5}=\dfrac{0,49.\left(-125\right)}{-\dfrac{343}{27}.\dfrac{81}{16}.\left(-1\right)}=-\dfrac{\dfrac{245}{4}}{\dfrac{1029}{16}}=\dfrac{20}{21}\)
1/2×(2×x-3)+105/2=-137/2
1/2×(2×x-3)=-137/2-105/2
1/2×(2×x-3)=-242/2
2×x-3=-242/2:1/2
2×x-3=-242
2.x=(-242)+3
2.x=239
x=239:2
x=239/2
A,-12×25-25×75-25×13
=[(-12)-75-13].25
=(-100).25
-2500
B,-50/7×49/10-35/2×-10/7+ -25/3× -9/5
=(-35)-(-25)+(-13)
=-23
C,-354+265-156+125
=[(-354)-156]+(265+125)
=(-510)+277
=-233
D,-74+40-50+16-35
=(-74)+40+(-50)+16+(-35)
=[(-74)+(-35)]+[40+(-50)+16]
=(-109)+26
=-83
E,-2/3×4/5+-4/5×4/3-0,125
=-2/3.4/5+4/5.(-4/3)-0,125
=4/5.[-2/3+(-4/3)]-0,125
=4/5.(-2)-0,125
=-8/5-0,125
=(-1,6)+(-0,125)
=-1,725
Lời giải:
a.
$A=1+3^2+3^4+....+3^{50}$
$3^2A=3^2+3^4+3^6+....+3^{52}$
$\Rightarrow 3^2A-A=(3^2+3^4+3^6+....+3^{52}) - (1+3^2+3^4+....+3^{50})$
$\Rightarrow 8A=3^{52}-1$
$\Rightarrow A=\frac{3^{52}-1}{8}$ (đpcm)
b.
Có: $8A=3^{52}-1=(3^4)^{13}-1=81^{13}-1$
$\Rightarrow 8A+1=81^{13}$ (đpcm)
Minh se giup ban
A=3+3^2+3^3+3^4+...+3^50+3^51
A=(3+3^2+3^3)+(3^4+3^5+3^6)+...+(3^49+3^50+3^51)
A=3*(1+3+9)+3^4*(1+3+9)+...+3^49*(1+3+9)
A=3^13+3^4*13+...+3^49*13
Moi thua so cua A deu co thua so 13 nen A chia het cho 13
a, 1+2+3+4+5+6+7+8+9=
(1+9)+(2+8)+(3+7)+(4+6)+5
=10+10+10+10+5
=45
b,(12+8)+(13+7)
=20+20
=40
c,(50+50)+(60+40)
=100+100
=200
= -1200
50 - 50 : [ 3 . ( 8 - 4 ) + 13 ]
= 50 - 50 : [ 3 . 4 + 13 ]
= 50 - 50 : [ 12 + 13 ]
= 50 - 50 : 25
= 50 - 2
= 48