\(\frac{7}{18}\)+\(\frac{5}{3}\)+\(1\frac{3}{9}\):\(\frac{55}{4}\)=???
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22 tháng 9 2016
Mình làm như thế này nek
\(\frac{\frac{1}{4}+\frac{3}{7}-\frac{4}{5}}{0,75+\frac{9}{7}-2\frac{2}{5}}+\frac{\frac{3}{14}-\frac{2}{10}+\frac{5}{18}+\frac{7}{66}}{\frac{6}{7}-\frac{4}{5}+\frac{10}{9}+\frac{14}{33}}\)
\(=\frac{\frac{1}{4}+\frac{3}{7}-\frac{4}{5}}{\frac{2}{4}+\frac{9}{7}-\frac{12}{5}}+\frac{\frac{1}{2}\cdot\left(\frac{3}{7}-\frac{2}{5}+\frac{5}{9}+\frac{7}{33}\right)}{2\cdot\left(\frac{3}{7}-\frac{2}{5}+\frac{5}{9}+\frac{7}{33}\right)}\)
\(=\frac{\frac{1}{4}+\frac{3}{7}-\frac{4}{5}}{3\cdot\left(\frac{1}{4}+\frac{3}{7}-\frac{4}{5}\right)}+\frac{\frac{1}{2}}{2}\)
\(=\frac{1}{3}+\frac{1}{4}=\frac{7}{12}\)
NN
2
6 tháng 11 2017
7/18 + 5/3 . 12/9 : 55/4
= 7/18 + 20/9 . 4/55
= 7/18 + 16/99
= 693/1782 + 288/1782
= 981/1782
17 tháng 8 2018
C = 1/3 + -3/4 + 3/5 + 1/57 + -1/36 + 1/15 + -2/9
C = ( 1/3 + 1/57 ) + ( -3/4 + -1/36 ) + ( 3/5 + 1/15 ) + -2/9
C = ( 19/57 + 1/57 ) + ( -27/36 + -1/36 ) + ( 9/15 + 1/15 ) + -2/9
C = 20/57 + -28/36 + 10/15 + -2/9
C = 20/57 + -7/9 + 2/3 + -2/9
C = ( 20/57 + 2/3 ) + ( -7/9 + -2/9 )
C = 58/57 + -1
C = 1/57
D = 1/2 + -1/5 + -5/7 + 1/6 + -3/35 + 1/3 + 1/41
D = ( 1/2 + 1/3 + 1/6 ) + ( -1/5 + -5/7 +-3/35 ) + 1/41
D = ( 3/6 + 2/6 + 1/6 ) + ( -7/35 + -25/35 + -3/35 ) + 1/41
D = 1 + -1 + 1/41
D = 1/41
E = -1/2 + 3/5 + -1/9 + 1/127 + -7/18 + 4/35 + 2/7
E = ( -1/2 + -1/9 + -7/18 ) + ( 3/5 + 4/35 ) + 1/127 + 2/7
E = ( -9/18 + -2/18 + -7/18 ) + ( 21/35 + 4/35 ) + 1/127 + 2/7
E = -1 + 5/7 + 1/257 + 2/7
E = -1 + ( 5/7 + 2/7 ) + 1/127
E = -1 + 1 + 1/127
E = 1/127
TS
1 tháng 4 2016
\(=\frac{-3}{7}\left(\frac{5}{9}+\frac{4}{9}+1\right)\)
\(=\frac{-3}{7}\cdot2\)
\(=\frac{-6}{7}\)
\(0:\left(1\frac{5}{6}-2\frac{1}{18}\right)\)
\(=0\)
HQ
Hà Quang Minh
Giáo viên
2 tháng 11 2023
a) $\frac{2}{3} = \frac{{2 \times 6}}{{3 \times 6}} = \frac{{12}}{{18}}$
Ta có $\frac{{12}}{{18}} > \frac{{11}}{{18}}$ nên $\frac{2}{3} > \frac{{11}}{{18}}$
b) $\frac{{36}}{{63}} = \frac{{36:9}}{{63:9}} = \frac{4}{7}$
Ta có $\frac{4}{7} < \frac{5}{7}$ nên $\frac{{36}}{{63}}$ < $\frac{5}{7}$
c)
$\frac{{55}}{{110}} = \frac{{55:55}}{{110:55}} = \frac{1}{2}$ ; $\frac{4}{8} = \frac{1}{2}$
Vậy $\frac{{55}}{{110}}$ = $\frac{4}{8}$
\(\frac{7}{18}\)\(+\frac{5}{3}\)\(+1\frac{3}{9}\)\(:\frac{55}{4}\)
\(=\frac{7}{18}\)\(+\frac{30}{18}\)\(+\frac{12}{9}\)\(x\frac{4}{55}\)
\(=\frac{7}{18}\)\(+\frac{30}{18}\)\(+\frac{4}{3}\)\(x\frac{4}{55}\)
\(=\frac{37}{18}\)\(+\frac{16}{165}\)\(=\frac{2035}{990}\)\(+\frac{96}{990}\)\(=\frac{2131}{990}\)
7/18 + 5/3 + 1/3/9 : 55/4 = 7/18 + 5/3 + 16/165
= 37/18 + 16/165
= 2/151/990