Ai giải dùm 3/4+1/4a:x=2/5
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7/4 - y* 5/6 = 1/2 - 1/3
\(\Leftrightarrow\) y*5/6 = 7/4 -1/2 + 1/3 = 19/12
\(\Leftrightarrow\)y = 19/12 : 5 /6 =19/10
vay y = 19/10
\(\frac{7}{4}-Yx\frac{5}{6}=\frac{1}{2}+\frac{1}{3}\)
\(\frac{7}{4}-Yx\frac{5}{6}=\frac{3}{6}+\frac{2}{6}\)
\(\frac{7}{4}-Yx\frac{5}{6}=\frac{5}{6}\)
\(Yx\frac{5}{6}=\frac{7}{4}-\frac{5}{6}\)
\(Yx\frac{5}{6}=\frac{42}{24}-\frac{20}{24}\)
\(Yx\frac{5}{6}=\frac{22}{24}\)
\(Yx\frac{5}{6}=\frac{11}{12}\)
\(Y=\frac{11}{12}:\frac{5}{6}\)
\(Y=\frac{11}{12}x\frac{6}{5}\)
\(Y=\frac{66}{60}\)
\(Y=\frac{11}{10}\)
ĐKXĐ: \(\left\{{}\begin{matrix}2x+5>=0\\4-2x>=0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}2x>=-5\\2x< =4\end{matrix}\right.\Leftrightarrow-\dfrac{5}{2}< =x< =2\)
\(x^2+\sqrt{2x+5}+\sqrt{4-2x}=4x-1\)
=>\(x^2-4+\sqrt{2x+5}-3+\sqrt{4-2x}=4x-1-7\)
=>\(\left(x-2\right)\left(x+2\right)+\dfrac{2x+5-9}{\sqrt{2x+5}+3}+\sqrt{4-2x}=4x-8\)
=>\(\left(x-2\right)\left[\left(x+2\right)+\dfrac{2}{\sqrt{2x+5}+3}-4\right]+\sqrt{4-2x}=0\)
=>\(-\left(2-x\right)\left[\left(x-2\right)+\dfrac{2}{\sqrt{2x+5}+3}\right]+\sqrt{2\left(2-x\right)}=0\)
=>\(\sqrt{2-x}\left[-\sqrt{2-x}\left(x-2+\dfrac{2}{\sqrt{2x+5}+3}\right)+\sqrt{2}\right]=0\)
=>\(\sqrt{2-x}=0\)
=>x=2(nhận)
\(=\left(-1\right).1.\left(-1\right).1.......\left(-1\right).1=1\)
(x+3)(x-2)+3x=4(x+3/4)
x(x+3)-2(x+3)+3x=4x+3
x2+3x-2x-6+3x-4x=3
x2+(3x-2x+3x-4x)-6=3
x2-6=3
x2=9
x2=32
=>x=|3|
x=3 hoặc x=-3
Giải Dùm Mình Đi