10.42 + 58.68 (21+x) : = 95 : 94
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\(\frac{\left(x^{95}+x^{94}\right)+.....+\left(x+1\right)}{\left(x^{31}+x^{30}\right)+.....+\left(x+1\right)}=\frac{x^{94}\left(x+1\right)+......+\left(x+1\right)}{x^{30}\left(x+1\right)+.....+\left(x+1\right)}=\frac{x^{94}+x^{92}+....+x^2+1}{x^{30}+x^{28}+....+x^2+1}=\frac{\left(x^2+1\right)x^{92}+x^{88}\left(x^2+1\right).....+\left(x^2+1\right)}{\left(x^2+1\right)x^{28}+\left(x^2+1\right)x^{24}+....+\left(x^2+1\right)}=\frac{x^{92}+x^{88}+......+x^4+1}{x^{28}+x^{24}+.....+x^4+1}=\frac{x^{88}\left(x^4+1\right)+x^{80}\left(x^4+1\right)+....+\left(x^4+1\right)}{x^{24}\left(x^4+1\right)+x^{16}\left(x^4+1\right)+.....+\left(x^4+1\right)}=\frac{x^{88}+x^{80}+....+1}{x^{24}+x^{16}+...+1}\)
\(=\frac{x^{80}\left(x^8+1\right)+x^{64}\left(x^8+1\right)+.....+\left(x^8+1\right)}{x^{16}\left(x^8+1\right)+\left(x^8+1\right)}=\frac{x^{80}+x^{64}+.....+1}{x^{16}+1}=\frac{x^{64}\left(x^{16}+1\right)+.....+x^{16}+1}{x^{16}+1}=x^{64}+x^{32}+1\)
Ta có : \(\dfrac{2x+5}{95}+\dfrac{2x+6}{94}+\dfrac{2x+7}{93}=\dfrac{2x+93}{7}+\dfrac{2x+94}{6}+\dfrac{2x+95}{5}\)
\(\Leftrightarrow\dfrac{2x+5}{95}+\dfrac{2x+6}{94}+\dfrac{2x+7}{93}-\dfrac{2x+93}{7}-\dfrac{2x+94}{6}-\dfrac{2x+95}{5}=0\)
\(\Leftrightarrow\dfrac{2x+5}{95}+1+\dfrac{2x+6}{94}+1+\dfrac{2x+7}{93}+1-\dfrac{2x+93}{7}-1-\dfrac{2x+94}{6}-1-\dfrac{2x+95}{5}-1=0\)
\(\Leftrightarrow\dfrac{2x+100}{95}+\dfrac{2x+6}{94}+\dfrac{2x+7}{93}-\dfrac{2x+100}{7}-\dfrac{2x+100}{6}-\dfrac{2x+100}{5}=0\)
\(\Leftrightarrow\left(2x+100\right)\left(\dfrac{1}{95}+\dfrac{1}{94}+\dfrac{1}{93}-\dfrac{1}{7}-\dfrac{1}{6}-\dfrac{1}{5}\right)=0\)
Thấy : \(\dfrac{1}{95}+\dfrac{1}{94}+\dfrac{1}{93}-\dfrac{1}{7}-\dfrac{1}{6}-\dfrac{1}{5}\ne0\)
\(\Rightarrow2x+100=0\)
\(\Leftrightarrow x=-50\)
Vậy ...
a, 3.(37 - \(x\)) - 56 = 1
3.(37 - \(x\)) = 1 + 56
3.(37 - \(x\)) = 57
37 - \(x\) = 57 : 3
37 - \(x\) = 19
\(x\) = 37 - 19
\(x\) = 18
b, 95 - (2\(x\) - 1).4 = 14
(2\(x\) - 1).4 = 95 - 14
(2\(x\) - 1).4 = 81
2\(x\) - 1 = 81 : 4
2\(x\) = \(\dfrac{81}{4}\) - 1
2\(x\) = \(\dfrac{85}{4}\)
\(x\) = \(\dfrac{85}{4}\) : 2
\(x\) = \(\dfrac{85}{8}\)
\(\frac{x-1}{95}+\frac{x-2}{94}=\frac{x-3}{93}+\frac{x-4}{92}\)
\(\Rightarrow\frac{x-1}{95}+\frac{x-2}{94}-\frac{x-3}{93}-\frac{x-4}{92}=0\)
\(\Rightarrow\left(\frac{x-1}{95}-1\right)+\left(\frac{x-2}{94}-1\right)-\left(\frac{x-3}{93}-1\right)-\left(\frac{x-4}{92}-1\right)=0\)
\(\Rightarrow\frac{x-96}{95}+\frac{x-96}{94}-\frac{x-96}{93}-\frac{x-96}{92}=0\)
\(\Rightarrow\left(x-96\right)\left(\frac{1}{95}+\frac{1}{94}-\frac{1}{93}-\frac{1}{92}\right)=0\)
\(\Rightarrow x-96=0\left(vì\frac{1}{95}+\frac{1}{94}-\frac{1}{93}-\frac{1}{92}\ne0\right)\)
\(=>x=96\)
A=[(38+17)+125]+29
A=175+29
A=204
B=312.3
B=936
C=1+1+1+1+1
C=5
D=(125:5).(36:9)
D=25.4
D=100
\(\frac{x+1}{96}+\frac{x+2}{95}=\frac{x+3}{94}+\frac{x+4}{93}\)
\(\Rightarrow\left(\frac{x+1}{96}+1\right)+\left(\frac{x+2}{95}+1\right)=\left(\frac{x+3}{94}+1\right)+\left(\frac{x+4}{93}+1\right)\)
\(\Rightarrow\frac{x+97}{96}+\frac{x+97}{95}=\frac{x+97}{94}+\frac{x+97}{93}\)
\(\Rightarrow\frac{x+97}{96}+\frac{x+97}{95}-\frac{x+97}{94}-\frac{x+97}{93}=0\)
\(\Rightarrow\left(x+97\right)\left(\frac{1}{96}+\frac{1}{95}-\frac{1}{94}-\frac{1}{93}\right)=0\)
Mà \(\frac{1}{96}+\frac{1}{95}-\frac{1}{94}-\frac{1}{93}\ne0\)
\(\Rightarrow x+97=0\)
\(\Rightarrow x=-97\)
Vậy x = -97
Có : \(\frac{x+1}{96}+\frac{x+2}{95}=\frac{x+3}{94}+\frac{x+4}{93}\)
\(\Leftrightarrow\)\(\left(\frac{x+1}{96}+1\right)+\left(\frac{x+2}{95}+1\right)\)= \(\left(\frac{x+3}{94}+1\right)+\left(\frac{x+4}{93}+1\right)\)
\(\Leftrightarrow\) \(\frac{x+97}{96}+\frac{x+97}{95}=\frac{x+97}{94}+\frac{x+97}{93}\)
\(\Leftrightarrow\) \(\frac{x+97}{96}+\frac{x+97}{95}-\frac{x+97}{94}-\frac{x+97}{93}=0\)
\(\Leftrightarrow\) \(\left(x+97\right)\left(\frac{1}{96}+\frac{1}{95}-\frac{1}{94}-\frac{1}{93}\right)=0\)
\(\Leftrightarrow\) \(\left(x+97\right)=0\) ( \(\frac{1}{96}+\frac{1}{95}-\frac{1}{94}-\frac{1}{93}\)) \(\ne0\)
\(\Leftrightarrow\)\(x=-97\)
Vậy \(x=-97\)
10.4 mũ 2 + 58.68
=160+3944
=4104
Cái còn lại bạn ko viết chia mấy nên mk ko trả lời nha
@nguyen anh ngoc chia 9 á