\(1+2^1+2^2+2^3+....+2^{50}\)
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là 6375
hãy k nếu bạn thấy đây là câu tl đúng :)
chúc bạn hok tốt :P
1 + 1 + 1 + 1 + 1 + 2 + 2 + 2 + 2 + 2 +...+ 50+50+50+50
= 1x5 + 2x5 + 3x5 +...+50x5
=5x(1+2+3+...+50)
=5x1275
=6375


\(B=1+\dfrac{1}{2}\cdot\dfrac{2\cdot3}{2}+\dfrac{1}{3}\cdot\dfrac{3\cdot4}{2}+...+\dfrac{1}{50}\cdot\dfrac{50\cdot51}{2}\)
\(=1+\dfrac{3}{2}+\dfrac{4}{2}+...+\dfrac{51}{2}\)
\(=\dfrac{50\cdot\dfrac{\left(51+2\right)}{2}}{2}=50\cdot\dfrac{53}{4}=662.5\)


\(E=-\dfrac{1}{3}\cdot\left(1+2+3\right)-\dfrac{1}{4}\left(1+2+3+4\right)-...-\dfrac{1}{50}\left(1+2+3+...+50\right)\)
\(=\dfrac{-1}{3}\cdot\dfrac{3\cdot4}{2}-\dfrac{1}{4}\cdot\dfrac{4\cdot5}{2}-...-\dfrac{1}{50}\cdot\dfrac{50\cdot51}{2}\)
\(=\dfrac{-4}{2}-\dfrac{5}{2}-...-\dfrac{51}{2}\)
\(=\dfrac{-\left(4+5+...+51\right)}{2}\)
\(=\dfrac{-\left(51+4\right)\cdot\dfrac{48}{2}}{2}=-\dfrac{1320}{2}=-660\)



A = 1 × 2 × 3 + 2 × 3 × 4 + .....+ 48 × 49 × 50
ta có 4 x A = 1 x 2 x 3 x 4 + 2 x 3 x 4 x (5 -1) + .....+ 48 × 49 × 50 x (51 - 47)
= 1 x 2 x 3 x 4 + 2 x 3 x 4 x 5 - 1 x 2 x 3 x 4 + ... + 48 x 49 x 50 x 51 - 47 x 48 x 49 x 50
= 48 x 49 x 50 x 51
suy ra A = (48 x 49 x 50 x 51) : 4
= 12 x 49 x 50 x 51
nhớ k cho mik nha rùi mik lm nốt cho
A = 1 × 2 × 3 + 2 × 3 × 4 + .....+ 48 × 49 × 50
ta có 4 x A = 1 x 2 x 3 x 4 + 2 x 3 x 4 x (5 -1) + .....+ 48 × 49 × 50 x (51 - 47)
= 1 x 2 x 3 x 4 + 2 x 3 x 4 x 5 - 1 x 2 x 3 x 4 + ... + 48 x 49 x 50 x 51 - 47 x 48 x 49 x 50
= 48 x 49 x 50 x 51
suy ra A = (48 x 49 x 50 x 51) : 4
= 12 x 49 x 50 x 51
Đặt: \(A=1+2^1+2^2+2^3+...+2^{50}\)
\(\Rightarrow2A=2^1+2^2+2^3+2^4+...+2^{51}\)
\(\Rightarrow2A-A=\left(2^1+2^2+2^3+2^4+...+2^{51}\right)-\left(1+2^1+2^2+2^3+...+2^{50}\right)\)
\(\Rightarrow A=2^{51}-1\)
1 + 21 + 22 + 23 + ... + 250
Ta có : Đặt A = 1 + 21 + 22 + 23 + ... + 250
2A = 2(1 + 21 + 22 + 23 + ... + 250)
2A = 2 + 22 + 23 + ... + 251
2A - A = ( 2 + 22 + 23 + ... + 251) - (1 + 21 + 22 + 23 + ... + 250)
A = 251 - 1