Tính: ( 3. 4 . 216 ) / 11 . 212 . 411 -169
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1: 8=2^3
2: 25=5^2
3: 4=2^2
4: 49=7^2
5: 81=9^2
6: 36=6^2
7: 100=10^2
8: 121=11^2
9: 144=12^2
10: 169=13^2
11: 27=3^3
12: 125=5^3
13: 1000=10^3
14: 32=2^5
15: 243=3^5
16: 343=7^3
17: 216=6^3
18: 64=4^3
19: 225=15^2
20: 128=2^7
D=\(\frac{\left(3.4.216\right)^2}{11.2^{13}.4^{11}-16^9}=\frac{3^2.2^4.\left(2^3.3^3\right)^2}{11.2^{13}.2^{22}-2^{36}}=\frac{2^4.3^2.2^6.3^6}{2^{35}\left(11-2\right)}=\frac{2^{10}.3^8}{2^{35}.3^2}\)
D= \(\frac{3^6}{2^{15}}\)
Dãy trên có 108 số số hạng
C = (2+4-6-8)+(10+12-14-16)+........+(210+212-214-216)
C= (-8)+(-8)+........+(-8)
C= (-8) x 108
C= (-864)
1: \(\dfrac{4}{23}+\dfrac{5}{21}+\dfrac{1}{2}-\dfrac{4}{23}+\dfrac{16}{21}\)
\(=1+\dfrac{1}{2}\)
\(=\dfrac{3}{2}\)
2: \(\left(\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}\right)-\left(\dfrac{79}{67}-\dfrac{28}{41}\right)\)
\(=\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}-\dfrac{79}{67}+\dfrac{28}{41}\)
\(=\dfrac{1}{3}\)
\(5487+8369=13856\)
\(37978-5169=32809\)
\(4\) x \(\dfrac{7}{4}=\dfrac{\text{4 x 7}}{4}=\dfrac{28}{4}=7\)
\(\dfrac{6}{11}:\dfrac{3}{4}=\dfrac{6}{11}\) x \(\dfrac{4}{3}=\dfrac{24}{33}=\dfrac{8}{11}\)
5487 + 8369 = 13 856
37 978 - 5169 = 32 809
4 x \(\dfrac{7}{4}\) = \(\dfrac{28}{4}\) = 7
\(\dfrac{6}{11}:\dfrac{3}{4}=\dfrac{6}{11}x\dfrac{4}{3}=\dfrac{24}{33}=\dfrac{8}{11}\)
Ta có \(\frac{3.4.2^{16}}{11.2^{12}.4^{11}-16^9}\)
\(=\frac{3.2^2.2^{16}}{11.2^{12}.2^{22}-2^{36}}\)
\(=\frac{3.2^{18}}{11.2^{34}-2^{36}}\)
\(=\frac{3.2^{18}}{2^{34}.\left(11-2^2\right)}\)
\(=\frac{3.2^{18}}{2^{34}.5}\)
\(=\frac{3}{2^{16}.5}\)
Ta có : \(\frac{3.4.2^{16}}{11.2^{12}.4^{11}-16^9}=\frac{3.2^2.2^{16}}{11.2^{12}.2^{22}-2^{36}}\)\(=\frac{3.2^{18}}{11.2^{34}-2^{36}}=\frac{2^{18}.3}{2^{34}.\left(11-2^2\right)}\)\(=\frac{2^{18}.3}{2^{34}.7}=\frac{3}{2^{16}.7}\)