Thực hiện phép tính
(x2 + x - 3)(x2 - x + 3)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(1,=\left(x+3\right)\left(x-2\right):\left(x+3\right)=x-2\\ 2,=\left(x-5\right)\left(x+6\right):\left(x+6\right)=x-5\\ 3,=\left[3x\left(2x-1\right)-5\right]:\left(2x-1\right)=3x.dư.\left(-5\right)\)
1)\(\left(x+x^2-6\right):\left(x+3\right)=\left[x\left(x+3\right)-2\left(x+3\right)\right]:\left(x+3\right)=\left[\left(x+3\right)\left(x-2\right)\right]:\left(x+3\right)=x-2\)
2) \(\left(x+x^2-30\right):\left(x+6\right)=\left[x\left(x+6\right)-5\left(x+6\right)\right]:\left(x+6\right)=\left[\left(x+6\right)\left(x-5\right)\right]:\left(x+6\right)=x-5\)
3) \(\left(5-3x+6x^2\right):\left(2x-1\right)=\left[3x\left(2x-1\right)+5\right]:\left(2x-1\right)=3x+\dfrac{5}{2x-1}\)
1.(2x+3).(x-5)+2x(3-x)+x-10
=2x^2 -10x+3x-15+6x-2x^2+x-10
=2x-25
2.(-x-2)3+(2x-4).(x2+2x+4)-x2.(x-6)
=-x^3+6x^2-12x-8+2x^3+4x^2+8x-4x^2+8x-16-x^3+6x^2
\(\dfrac{x+3}{x}-\dfrac{x}{x-3}+\dfrac{9}{x^2-3x}=\dfrac{x^2-9-x^2+9}{x\left(x-3\right)}=\dfrac{0}{x\left(x-3\right)}=0\)
(-2x - 1)(x2 + 5x - 3) - (x - 1)3
= -2x3 - 10x2 + 6x - x2 - 5x + 3 - x3 + 3x2 - 3x + 1
= -3x3 - 8x2 - 2x + 4
`@` `\text {Ans}`
`\downarrow`
`(x-3)^2 - x^2 + 10x - 7`
`= x^2 - 6x + 9 - x^2 + 10x - 7`
`= (x^2 - x^2) + (-6x + 10x) + (9-7)`
`= 4x + 2`
\(\left(x-3\right)^2-x^2+10x-7\)
\(=\left(x^2-6x+9\right)-x^2+10x-7\)
\(=\left(x^2-x^2\right)-\left(6x-10x\right)+\left(9-7\right)\)
\(=4x+2\)
\(=2\left(2x+1\right)\)
\(\left(x^2+x-3\right)\left(x^2-x+3\right)=x^4-\left(x-3\right)^2=x^4-x^2+6x-9\)