Chỉ mình bài số4 vs ạ cảm ơn nhìu
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DT
Đỗ Thanh Hải
CTVVIP
28 tháng 4 2021
1 can => could
2 making-shoe => shoe-making
3 writing => written
4 running => to run
5 from => in
6 did the christmas tree come => the christmas tree came
7 much => many
8 have => are
9 pleasing => pleased
10 decorating => decorate
2 tháng 1 2022
1, The homework is too difficult for him to do
2, The homework isn't easy enough for him to do
3, The homework is so difficult that he can't do it
4, It is such difficult homework that he can't do it
DT
7 tháng 1 2022
1. My sister says she went to school by bus this morning.
My sister said she had gone to school by bus that morning.
2. Nga says she have done her homework.
Nga said she had done her homework.
7 tháng 1 2022
1, My sister says that she goes to school by bus this morning
My sister said that she had gone to school by bus this morning
2, Nga says that she have done her homework
Nga said that she had done her homework
DT
24 tháng 12 2021
1.........................................
=>the computer hasn't been fixed by them yet
2.......................................
=>Last night I was helped by a stranger.
23 tháng 10 2023
3: \(\left(\dfrac{1}{\sqrt{2}-1}-\dfrac{1}{\sqrt{2}+1}\right):\sqrt{3-2\sqrt{2}}\)
\(=\dfrac{\sqrt{2}+1-\sqrt{2}+1}{2-1}:\left(\sqrt{2}-1\right)\)
\(=\dfrac{2}{\sqrt{2}-1}=2\left(\sqrt{2}+1\right)=2\sqrt{2}+2\)
5:
\(\dfrac{\sqrt{5}+\sqrt{3}}{\sqrt{5}-\sqrt{3}}+\dfrac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}\)
\(=\dfrac{\left(\sqrt{5}+\sqrt{3}\right)^2+\left(\sqrt{5}-\sqrt{3}\right)^2}{\left(\sqrt{5}-\sqrt{3}\right)\left(\sqrt{5}+\sqrt{3}\right)}\)
\(=\dfrac{8+2\sqrt{15}+8-2\sqrt{15}}{2}=\dfrac{16}{2}=8\)
6:
\(\dfrac{\sqrt{5}-1}{\sqrt{5}+1}-\dfrac{\sqrt{5}+1}{\sqrt{5}-1}\)
\(=\dfrac{\left(\sqrt{5}-1\right)^2-\left(\sqrt{5}+1\right)^2}{\left(\sqrt{5}+1\right)\left(\sqrt{5}-1\right)}\)
\(=\dfrac{6-2\sqrt{5}-6-2\sqrt{5}}{4}=\dfrac{-4\sqrt{5}}{4}=-\sqrt{5}\)
4:
\(\dfrac{6}{\sqrt{2}-\sqrt{3}+3}\)
\(=\dfrac{6\left(\sqrt{2}-\sqrt{3}-3\right)}{\left(\sqrt{2}-\sqrt{3}-3\right)\left(\sqrt{2}-\sqrt{3}+3\right)}\)
\(=\dfrac{6\left(\sqrt{2}-\sqrt{3}-3\right)}{5-2\sqrt{6}-9}=\dfrac{-6\left(\sqrt{2}-\sqrt{3}-3\right)}{4+2\sqrt{6}}\)
\(=\dfrac{-3\left(\sqrt{2}-\sqrt{3}-3\right)}{\sqrt{6}+2}=\dfrac{-3\left(\sqrt{2}-\sqrt{3}-3\right)\left(\sqrt{6}-2\right)}{2}\)
\(=\dfrac{-3\left(2\sqrt{3}-2\sqrt{2}-3\sqrt{2}+2\sqrt{3}-6\sqrt{3}+6\right)}{2}\)
\(=\dfrac{-3\left(-2\sqrt{3}-5\sqrt{2}+6\right)}{2}\)
13 tháng 2 2022
representatives
natural - include
recycling
mixture
environmentally
packaging
PL
1
Hình bình hành có đáy là 63cm , chiều cao kém đáy 14cm nên chiều cao bằng:
63-14=49(cm)
Diện tích hình bình hành là:
63x14=882(cm2)
Vậy diện tích hình bình hành là 882 cm2