(3xx-4):2+1/4=3/4
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a. \(\dfrac{5}{7}+\dfrac{4}{3}:x=\dfrac{1}{7}\)
<=> \(\dfrac{5}{7}+\dfrac{4}{3}.\dfrac{1}{x}=\dfrac{1}{7}\)
<=> \(\dfrac{5}{7}+\dfrac{4}{3x}=\dfrac{1}{7}\) ĐKXĐ: x \(\ne\) 0
<=> \(\dfrac{15x}{21x}+\dfrac{28}{21x}=\dfrac{3x}{21x}\)
<=> 15x + 28 = 3x
<=> 15x - 3x = -28
<=> 12x = -28
<=> x = \(\dfrac{-28}{12}=-\dfrac{7}{3}\)
b. \(\dfrac{5}{3}x.\dfrac{-1}{4}=\dfrac{2}{6}\)
<=> \(\dfrac{-5x}{12}=\dfrac{2}{6}\)
<=> -5x . 6 = 12 . 2
<=> -30x = 24
<=> x = \(-\dfrac{4}{5}\)
`@` `\text {Ans}`
`\downarrow`
\(\dfrac{2}{3}\times x-\dfrac{x}{2}-\dfrac{1}{2}=\dfrac{1}{4}?\)
`=>`\(\dfrac{2}{3}x-\dfrac{x}{2}-\dfrac{1}{2}=\dfrac{1}{4}\)
`=>`\(\dfrac{4x}{6}-\dfrac{3x}{6}-\dfrac{1}{2}=\dfrac{1}{4}\)
`=>`\(\dfrac{x}{6}-\dfrac{1}{2}=\dfrac{1}{4}\)
`=>`\(\dfrac{x}{6}=\dfrac{1}{4}+\dfrac{1}{2}\)
`=>`\(\dfrac{x}{6}=\dfrac{3}{4}\)
`=> 4x=3*6`
`=> 4x=18`
`=> x=`\(\dfrac{18}{4}=\dfrac{9}{2}=4,5\)
Vậy, `x=4,5.`
\(\href{https://hoc24.vn/vip/14874167551162}{\text{_KaizulvG_}}\)
a)\(\frac{2}{3}\cdot x+\frac{1}{4}=\frac{5}{6}\)
\(\frac{2}{3}\cdot x=\frac{5}{6}-\frac{1}{4}=\frac{7}{12}\)
\(x=\frac{7}{12}:\frac{2}{3}=\frac{7}{8}\)
b) \(\frac{7}{12}-\frac{5}{6}\cdot x=\frac{1}{4}:\frac{2}{3}\)
\(\frac{7}{12}-\frac{5}{6}\cdot x=\frac{3}{8}\)
\(\frac{5}{6}\cdot x=\frac{7}{12}-\frac{3}{8}=\frac{5}{24}\)
\(x=\frac{5}{24}:\frac{5}{6}=\frac{1}{4}\)
c) \(2\frac{1}{3}-\left(x+1\right)=\frac{5}{9}\)
\(\frac{7}{3}-\left(x+1\right)=\frac{5}{9}\)
\(x+1=\frac{7}{3}-\frac{5}{9}=\frac{16}{9}\)
\(x=\frac{16}{9}-1=\frac{7}{9}\)
d) \(\frac{2\cdot x+1}{15}=\frac{3}{5}\)
\(\left(2\cdot x+1\right):15=\frac{3}{5}\)
\(2\cdot x+1=\frac{3}{5}\cdot15=9\)
\(2\cdot x=9-1=8\)
\(x=8:2=4\)
a, 2/3 . x +1/4=5/6
2/3 . x=5/6-1/4
2/3 . x=10/12 -3/12
2/3 . x=7/12
x= 7/12 : 2/3
x=7/8
Vậy x=7/8
3x/4 + 3x/28 + 3x/70 + ... + 3x/304 = 18/19
=> x(3/1*4 + 3/4*7 + 3/7*10 + ... + 3/16*19) = 18/19
=> x(1 - 1/4 + 1/4 - 1/7 + 1/7 - 1/10 + ... + 1/16 - 1/19) = 18/19
=> x(1 - 1/19) = 18/19
=> x*18/19 = 18/19
=> x = 1
\(3.\frac{x}{4}+3.\frac{x}{28}+3.\frac{x}{70}+...+3.\frac{x}{304}=\frac{18}{19}\)
\(3.\left(\frac{x}{4}+\frac{x}{28}+\frac{x}{70}+...+\frac{x}{304}\right)\)
\(\frac{x}{4}+\frac{x}{28}+\frac{x}{70}+...+\frac{x}{304}=\frac{18}{19}:3=\frac{6}{19}\)
Nhân hai vế với 3/x ta được
\(\frac{3}{x}\left(\frac{x}{4}+\frac{x}{28}+\frac{x}{70}+...+\frac{x}{304}\right)=\frac{6}{19}.\frac{3}{x}\)
\(\frac{3}{x}.\frac{x}{4}+\frac{3}{x}.\frac{x}{28}+\frac{3}{x}.\frac{x}{70}+...+\frac{3}{x}.\frac{x}{304}=\frac{18}{19.x}\)
\(\frac{3}{4}+\frac{3}{28}+\frac{3}{70}+...+\frac{3}{304}=\frac{18}{19}:x\)
\(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{16.19}=\frac{18}{19}:x\)
\(1-\frac{1}{19}=\frac{18}{19}:x\)
\(\frac{18}{19}=\frac{18}{19}:x\)
\(x=\frac{18}{19}:\frac{18}{19}=1\)
Chúc bạn học tốt !!!
P/s: Không hiểu chỗ nào cứ ib
\(\dfrac{1}{4}+\dfrac{1}{3}\times X=\dfrac{1}{2}\\ \dfrac{1}{3}\times X=\dfrac{1}{2}-\dfrac{1}{4}=\dfrac{1}{4}\\ X=\dfrac{1}{4}:\dfrac{1}{3}=\dfrac{1}{4}\times3=\dfrac{3}{4}\)
\(\left(3\times x-4\right):2+\frac{1}{4}=\frac{3}{4}\)
\(\left(3\times x-4\right):2=\frac{3}{4}-\frac{1}{4}\)
\(\left(3\times x-4\right):2=\frac{1}{2}\)
\(\left(3\times x-4\right)=\frac{1}{2}\times2\)
\(3\times x-4=1\)
\(3\times x=1+4\)
\(3\times x=5\)
\(x=5:3\)
\(x=\frac{5}{3}\)