so sánh :
a . \(\frac{16}{27}\) và \(\frac{15}{29}\)
b . \(\frac{26}{50}\) và \(\frac{14}{29}\)
c . \(\frac{327}{326}\)và \(\frac{326}{325}\)
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\(\frac{327}{326}=1+\frac{1}{326};\frac{326}{325}=1+\frac{1}{325}\)
Vì \(\frac{1}{326}
\(\frac{327}{326}=1\frac{1}{326}\) còn \(\frac{326}{325}=1\frac{1}{325}\)
bây giờ ta chỉ còn so sánh \(1\frac{1}{326}\)với \(1\frac{1}{325}\)
1 = 1 so sánh \(\frac{1}{326}\)với \(\frac{1}{325}\)
so sánh phân số có cùng tử số thì phân số nào có mấu số bé hơn thì phân số đó lớn hơn
vậy \(\frac{1}{326}< \frac{1}{325}\)=> \(\frac{327}{326}< \frac{326}{325}\)
Đáp số : \(\frac{327}{326}< \frac{326}{325}\)
16/27>1529
1995/1996<1996/1997
327/326<326/325
43/6>39/9
nhớ nhé
nhớ tích đúng cho mình nhé đảm bảo 1000000000000000000000000000000000000000000000000000000000000%là đúng
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)
\(\Leftrightarrow\frac{x+2}{327+1}+\frac{x+3}{326+1}+\frac{x+4}{325+1}+\frac{x+5}{324+1}+\frac{x+349}{5-4}=0\)
\(\Leftrightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
\(\Leftrightarrow\left(x+329\right)\cdot\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)
Do \(\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)\ne0\)
Nên \(x+329=0\Rightarrow x=-329\)
\(\Leftrightarrow\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}+1+\frac{x+324}{5}=0\)
\(\Leftrightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
\(\Leftrightarrow\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)\(Vì\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)\ne0\)
=> x+329=0
=> x = -329
b) \(\Leftrightarrow\left(x+2\right)\left(\frac{1}{11}+\frac{1}{12}+\frac{1}{13}-\frac{1}{14}-\frac{1}{15}\right)=0\)\(Vì\left(\frac{1}{11}+\frac{1}{12}+\frac{1}{13}-\frac{1}{14}-\frac{1}{15}\right)\ne0\)
=> x+2 =0 => x =-2
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0.\)
\(1+\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}-4+\frac{x+349}{5}=0\)
\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
\(\left(x+329\right).\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)
\(\Rightarrow x+329=0\)
\(\Rightarrow x=-329\)
Study well
\(\Rightarrow\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}+1+\frac{x+349}{5}-4=0\)
\(\Rightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
\(\Rightarrow\left(x+329\right).\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)
Mà \(\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)\ne0\)
Nên \(x+329=0\Rightarrow x=-329\)
Vậy \(x=-329\)
Chúc bạn học tốt !!!
a,\(\frac{16}{27}\)> \(\frac{15}{29}\)
b,\(\frac{26}{50}\)> \(\frac{14}{29}\)
c,\(\frac{327}{326}\)< \(\frac{326}{325}\)
Tk nha!!
\(a,\frac{16}{27}>\frac{15}{29}\)
\(b,\frac{26}{50}>\frac{14}{29}\)
\(c,\frac{327}{326}< \frac{326}{325}\)
~ Chúc bạn học tốt ~