3/2*3*4 + 3/3*4*5 + 3/4*5*6 +..............+ 3/100*101*102
giup minh ti minh dang can gap traong 1 tieng
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\(\dfrac{5}{6}x-\dfrac{3}{4}=\dfrac{-1}{4}+\dfrac{2}{3}\)
\(\Leftrightarrow\dfrac{5}{6}x=\dfrac{7}{6}\)
\(\Rightarrow x=\dfrac{7}{5}\)
b) \(-1\dfrac{1}{2}-\dfrac{2}{3}x=\dfrac{5}{6}-\left(\dfrac{-2}{5}\right)\)
\(\Leftrightarrow\dfrac{2}{3}x=-\dfrac{41}{15}\)
\(\Rightarrow x=-\dfrac{41}{10}\)
c) \(\left(\dfrac{4}{5}:x+1,5\right):\dfrac{2}{3}=-1,5\)
\(\Leftrightarrow\dfrac{8+15x}{10x}.\dfrac{3}{2}=\dfrac{-3}{2}\)
\(\Leftrightarrow\dfrac{24+45x}{20x}=\dfrac{-3}{2}\)
\(\Leftrightarrow-60x=48+90x\)
\(\Rightarrow x=-0,32\)
d) \(\dfrac{4}{3}x-\dfrac{2}{3}=\dfrac{1}{4}-x\)
\(\Leftrightarrow\dfrac{4x-2}{3}=\dfrac{1-4x}{4}\)
\(\Rightarrow16x-8=3-12x\)
\(\Rightarrow x=\dfrac{11}{28}\)
a) -1/8 -2x/5-1/3=3
-2x/5=3+1/8+1/3
-2x/5=83/24
-2x=(83×5)/24=415/24
x = (415÷-2)/24= -415/48
b) -7/3 -(25/6 -4/3+ 3/2)
= -7/3 -13/3 = -20/3
a) 4/7 + 7/20 + 1/4 b) 21,15 + 3/5 + 3/4
= 4/7 + 7/20 + 5/20 = 21,15 + 0,6 + 0,75
= 4/7 + 3/5 = 22,5
= 20/35 + 21/35
= 41/35
a,\(\frac{4}{7}\) \(+\frac{7}{20}\) \(+\frac{1}{4}\)
\(=\frac{4}{7}\) \(+\frac{7}{20}\) \(+\frac{5}{20}\)
\(=\frac{4}{7}\) \(+\frac{3}{5}\)
\(=\frac{20}{35}\)\(+\frac{21}{35}\)
\(=\frac{41}{35}\)
#Hemingson
S= 2-1-2-3-4-....-201-202
= 2-(1+2+3+4+....+202)
=2- (202:2)( 202+1)
= 2- 101.203
mk nghĩ câu hỏi này ko xứng tầm lớp 5 đâu!
\(\frac{3}{2.3.4}+\frac{3}{3.4.5}+...+\frac{3}{100.101.102}\)
\(=\frac{3}{2}\left(\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{100.101}-\frac{1}{101.102}\right)\)
\(=\frac{3}{2}\left(\frac{1}{6}-\frac{1}{101.102}\right)\)