a) 5x+5y-x^2-2xy-y^2
b,x^5-x^4+x^3_x^2
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a) \(x^2+4x+4-y^2\)
\(=\left(x^2+2.x.2+2^2\right)-y^2\)
\(=\left(x+2\right)^2-y^2\)
\(=\left(x+2+y\right)\left(x+2-y\right)\)
\(a,=\left(x+2\right)^2-y^2=\left(x-y+2\right)\left(x+y+2\right)\\ b=\left(x-2y\right)^2-16=\left(x-2y-4\right)\left(x-2y+4\right)\\ c,=x\left(x^2+2xy+y^2\right)=x\left(x+y\right)^2\\ d,=5\left(x+y\right)-\left(x+y\right)^2=\left(5-x-y\right)\left(x+y\right)\\ e,=x^4\left(x-1\right)+x^2\left(x-1\right)\\ =x^2\left(x^2+1\right)\left(x-1\right)\)
a) 25x2 - y2 + 4y - 4
= (5x)2 - (y - 2)2
= (5x + y - 2)(5x - y + 2)
b) a2 + b2 - x2 - y2 + 2ab - 2xy
= (a2 + 2ab + b2) - (x2 + 2xy + y2)
= (a + b)2 - (x + y)2
= (a + b + x + y)(a + b - x - y)
c) 5x2(x - 1) + 10xy(x - 1) - 5y2(1 - x)
= 5x2(x - 1) + 10xy(x - 1) + 5y2(x - 1)
= (x - 1)(5x2 + 10xy + 5y2)
= 5(x - 1)(x2 + 2xy + y2)
= 5(x -1)(x + y)2
d) x5 - x4y - xy4 + y5
= x4(x - y) - y4(x - y)
= (x - y)(x4 - y4)
= (x - y)(x2 - y2)(x2 + y2) = (x - y)2(x + y)(x2 + y2)
e: \(49-x^2-2xy-y^2\)
\(=49-\left(x+y\right)^2\)
\(=\left(7-x-y\right)\left(7+x+y\right)\)
d: \(16x^2-24xy+9y^2=\left(4x-3y\right)^2\)
a, \(\left(5x-4\right)\left(5x+4\right)-\left(5x-4\right)^2=\left(25x^2-16\right)-\left(25x^2-40x+16\right)=40x-32\)
b,\(\left(5x+3\right)^2-\left(4x-1\right)^2-\left(9x^2+8\right)=\left(x+4\right)\left(9x-2\right)-\left(9x^2+8\right)\)
\(=9x^2+34x-8-\left(9x^2+8\right)=34x\)
c,\(2\left(x-5y\right)\left(x+5y\right)+\left(x+5y\right)^2+\left(x-5y\right)^2=\left(2x\right)^2=4x^2\)
\(1,=\left(x-3\right)\left(x+3\right)\\ 2,=\left(x-y\right)\left(5+a\right)\\ 3,=\left(x+3\right)^2\\ 4,=\left(x-y\right)\left(10x+7y\right)\\ 5,=5\left(x-3y\right)\\ 6,=\left(x-y\right)^2-z^2=\left(x-y-z\right)\left(x-y+z\right)\)
b)x2+2xy+y2-16=(x+y)2-42=(x+y+4)(x+y-4)
c)3x2+5x-3xy-5y=x(3x+5)-y(3x+5)=(3x+5)(x-y)
d)4x2-6x3y-2x2+8x=2x(2x-3x2y-x+4)
e)x2-4-2xy+y2=(x2-2xy+y2)-4=(x-y)2-22=(x-y-2)(x-y+2)
k)x2-y2-z2-2yz=x2-(y+z)2=(x-y-z)(x+y+z)
m)6xy+5x-5y-3x2-3y2=3(x2-2xy+y2)+5(x-y)=3(x-y)2+5(x-y)=(x-y)(3x-3y+5)
đề bài là phân tích đa thứ thành nhân tử nhé
\(5x+5y-x^2-2xy-y^2\)
\(=\left(5x+5y\right)-\left(x^2+2xy+y^2\right)\)
\(=5\left(x+y\right)-\left(x+y\right)^2\)
\(=\left(5-x-y\right)\left(x+y\right)\)