tim x
99-3.(x+17)=45
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\(\left(100+58\right)\times58+\left(200-42\right)\times12\)
\(=158\times58+158\times12\)
\(=158\times\left(58+12\right)\)
\(=158\times70=11060\)
\(128\times72+14\times256\)
\(=128\times72+14\times2\times128\)
\(=128\times\left(72+28\right)\)
\(=128\times100=12800\)
-45:(3x-17)=3^2
⇒ -45:(3x-17)= 9
⇒ 3x-17 =-45:9
⇒3x-17 =-5
⇒3x =-5+17
⇒3x =12
⇒ x = 12:3=4
Vậy: x=4
99 - 3(x + 17) = 45
=> 3(x + 17) = 99 - 45
=> 3x + 51 = 54
=> 3x = 54 - 53
=> 3x = 3
=> x = 3 : 3
=> x = 1
vậy_
a,99-3x-51=45
3x=45+51-99
3x=-3
x=-1
b,x5:8=4
x5=32
x=2
c,3.x3=375
x3=125
x=5
d,12.x-33=35
12x=276
x=23
e,4x5=128
x5=32
x=2
g,2x:4=16
2x=64
x=6
a. \(\Leftrightarrow\) (3.x+4):12 = 19-17
\(\Leftrightarrow\)(3.x+4):12 = 2
\(\Leftrightarrow\)3.x+4 = 24 \(\Leftrightarrow\)3.x = 20 \(\Leftrightarrow\)x = \(\frac{20}{3}\)
b. \(\Leftrightarrow\)45: (2.x+1) = 3 \(\Leftrightarrow\)2.x+1 = 15 \(\Leftrightarrow\)2.x = 14 \(\Leftrightarrow\)x = 7
c. \(\Leftrightarrow\)72.(x+1) = 360 \(\Leftrightarrow\)x+1 = 5\(\Leftrightarrow\)x = 4
d.\(\Leftrightarrow\)(2.x+3).11 = 253\(\Leftrightarrow\)2.x+3 = 23\(\Leftrightarrow\)2.x = 20\(\Leftrightarrow\)x = 10
a )
\(x+\frac{12}{15}=\frac{7}{5}\)
\(\Rightarrow x=\frac{7}{5}-\frac{12}{15}\)
\(\Rightarrow x=\frac{7}{5}-\frac{4}{5}\)
\(\Rightarrow x=\frac{3}{5}\)
Vậy \(x=\frac{3}{5}\)
b )
\(x-\frac{6}{8}=\frac{3}{15}\)
\(\Rightarrow x-\frac{3}{4}=\frac{1}{5}\)
\(\Rightarrow x=\frac{1}{5}+\frac{3}{4}\)
\(\Rightarrow x=\frac{4}{20}+\frac{15}{20}\)
\(\Rightarrow x=\frac{19}{20}\)
Vậy \(x=\frac{19}{20}\)
~ Ủng hộ nhé
\(x+\frac{12}{15}=\frac{7}{5}\)
\(\Rightarrow x=\frac{7}{5}-\frac{12}{15}\)
\(\Rightarrow x=\frac{7}{5}-\frac{4}{5}\)
\(\Rightarrow x=\frac{3}{5}\)
a =143
b = 2510
c 28 x 73 = 2044
cái câu c tính nhẩm chết liền
d [ 1700 - 340 +17 ] : 17 = 81
2 . Tìm x
a 7 . [ x - 3 ] - 6 = 1
7 . [ x - 3 ] = 1+6
7 . [ x - 3 ] = 7
x - 3 = 7 : 7
x - 3 =1
x=3+1=4
b
[x+5] .2:11=6
[x+5] x 2 = 6 x 11
[ x + 5 ] x 2 = 66
x+2=66:2
x+2=33
x=33-2=31
Bài 1
a, \(45+98=143\)
b, \(2605-95=2510\)
c,\(28.73+28\)
\(=28.\left(73+1\right)\)
\(=28.74\)
\(=2072\)
d,\(\left[1700-340+17\right]:17\)
\(=1700:17-340:17+17:17\)
\(=100-20+1\)
\(=81\)
Bài 2
a, \(7.\left(x-3\right)-6=1\)
\(\Leftrightarrow7.\left(x-3\right)=7\)
\(\Leftrightarrow x-3=1\)
\(\Leftrightarrow x=4\)
b, \(\left(x+2\right).2:11=6\)
\(\Leftrightarrow\left(x+2\right).2=66\)
\(\Leftrightarrow x+2=33\)
\(\Leftrightarrow x=31\)
a) x+(-45)=(-62)+17
=>x-45=-45
=>x=-45+45
=>x=0
b) x+29=/-43/+(-43)
=>x+29=43-43
=>x+29=0
=>x=-29
c) 5+/x+1/=29
=>/x+1/=29-5=24
\(\orbr{\begin{cases}x+1=24\\x+1=-24\end{cases}}\Rightarrow\orbr{\begin{cases}x=23\\x=-25\end{cases}}\)
P/s tham khảo bài mình nha
a ) x + (-45) =-45
= > x = 0
b ) x + 29 = 0
=> x = -29
c ) => /x+1/ = 29-5
/x+1/ = 24
=> x+1 = + - 24
TH1 : x+1=24
=> x =23
th2 : x+1 = -24
=> x =-25
vậy x thuộc { 23 ; -25}
A = 1.2 + 2.3 + 3.4 + ... + 98.99
3A = 1.2.3 + 2.3.3 + 3.4.3 + ...+ 98.99.3
3A = 1.2.3 + 2.3.(4 -1) + 3.4.(5 - 2) + ...+ 98.99.(100 - 97)
3A = (1.2.3 + 2.3.4 + 3.4.5 + ... + 98.99.100) - (0.1.2 + 1.2.3 + 2.3.4 + ... + 97.98.99)
3A = 1.2.3 + 2.3.4 + 3.4.5 + ... + 98.99.100
3A = 98.99.100
=> A = \(\frac{98.99.100}{3}=323400\)
3.(x+17) = 144
x+17 = 48
x= 25
\(99-3\cdot\left(x+17\right)=45\)
\(3\cdot\left(x+17\right)=99-45\)
\(3\cdot\left(x+17\right)=54\)
\(x+17=54\div3\)
\(x+17=18\)
\(x=18-17\)
\(x=1\)