Question

[Soke Soắn]

Cho \(\dfrac{a}{b}=\dfrac{c}{d}\)

CMR \(\dfrac{a.b}{c.d}=\dfrac{a^2-b^2}{c^2-d^2}\)

Answer 1

[Trần Minh Hoàng]

Đặt \(\dfrac{a}{b}=\dfrac{c}{d}=k\Rightarrow\left\{{}\begin{matrix}a=bk\\c=dk\end{matrix}\right.\)

Ta có:

\(\dfrac{ab}{cd}=\dfrac{bk.b}{dk.d}=\dfrac{b^2}{d^2}\) (1)

\(\dfrac{a^2-b^2}{c^2-d^2}=\dfrac{\left(bk\right)^2-b^2}{\left(dk\right)^2-d^2}=\dfrac{b^2k^2-b^2}{d^2k^2-d^2}=\dfrac{b^2\left(k^2-1\right)}{d^2\left(k^2-1\right)}=\dfrac{b^2}{d^2}\) (2)

Từ (1) và (2) suy ra \(\dfrac{ab}{cd}=\dfrac{a^2-b^2}{c^2-d^2}\)

Answer 2

[Huyền Anh Lê]

tick cho bạn nha