3^x-1+5.3^x-1=72
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\(3^x+5.3^{x-1}=72\)
=> \(3^{x-1}.3+5.3^{x-1}=72\)
=> \(3^{x-1}.\left(3+5\right)=72\)
=> \(3^{x-1}.8=72\)
=> \(3^{x-1}=72:8\)
=> \(3^{x-1}=9\)
=> \(3^{x-1}=3^2\)
=> \(x-1=2\)
=> \(x=2+1\)
=> \(x=3\)
Chúc học tốt
\(9^{x+1}-5.3^{2x}=72\)
\(\rightarrow9^x.9-5.\left(3^2\right)^x=72\)
\(\rightarrow9^x.9-5.9^x=72\)
\(\rightarrow9^x\left(9-5\right)=72\)
\(\rightarrow4.9^x=72\)
\(\rightarrow9^x=18\)
\(\Rightarrow x=1,315...\)
Vậy \(x=1,315...\)
1)Tính:
4.{624:[5+7.(72:23-6)]}-5.3
=4.{624:[5+7.(72:8-6]}-15
=4.{624:[5+7.(9-6)]}-15
=4.{624:[5+7.3]}-15
=4.{624:26}-15
=4.24-15
=81
2) Tìm x biết
a)108-x=32.7
108-x=224
x=108-224
x=-116
b)15-(5x-4):3=23
(5x-4):3=15-23
(5x-4):3=-8
5x-4=-8.3
5x-4=-24
5x=-24+4
5x=-20
x=-20:5
x=-4
Bài 1 :
4 . {624 :[5 + 7 . (72 : 23 - 6)]} - 5 . 3
= 4 . {624 :[ 5 + 7 . (72 : 8 - 6)]} - 15
= 4 . {624 : [5 + 7 . (9 - 6)]} - 15
= 4 . [624 : (5 + 7 . 3)] - 15
= 4 . [624 : (5 + 21)] - 15
= 4 . (624 : 26) - 15
= 4 . 24 - 15
= 96 - 15
= 81
3^x-1+5.3^x-1=162
3^x-1.(1+5)=162
3^x-1.6=162
3^x-1=162:6
3^x-1=27
3^x-1=3^3
x-1=3
x=3+1
x=4
\(\Leftrightarrow3^x\cdot\dfrac{1}{3}+5\cdot3^x\cdot\dfrac{1}{3}=72\)
\(\Leftrightarrow3^x\cdot2=72\)
\(\Leftrightarrow3^x=36\)
hay \(x\in\varnothing\)