1.Tính:
a)A=625-(61-17).12 +(27+14):17
b)B=-126-(4^2-5)^2+870:29
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a) A=625–(61–17).12+(27+27):17A=625–(61–17).12+(27+27):17
=625–528+3=100=625–528+3=100
b) B=−126–(42–5)2+870:29B=−126–(42–5)2+870:29
=−126–112+30=−126–112+30
=−126–121+30=−217
\(A=625-\left(61-17\right)\cdot12+\left(27+24\right)\div17\)
\(A=625-44\cdot12+51\div17\)
\(A=625-528+3\)
\(A=100\)
\(B=-126-\left(4^2-5^2\right)+870-29\)
\(B=-126-\left(16-25\right)+870-29\)
\(B=-126-\left(-9\right)+870-29\)
\(B=-117+870-29\)
\(B=753-29\)
\(B=724\)
Chúc bn hok tốt
1) A \(=625-\left(61-17\right).12+\left(27+24\right):17\)
\(\Leftrightarrow A=625-44.12+51:17\)
\(\Leftrightarrow A=625-528+3\)
\(\Leftrightarrow A=100\)
Vậy A = 100
2) B \(=-126-\left(4^2-5^2\right)+870-29\)
\(\Leftrightarrow B=-126-\left(16-25\right)+870-29\)
\(\Leftrightarrow B=-126-16+25+870-29\)
\(\Leftrightarrow B=724\)
Vậy B = 724
b) 4.(–5)2 + 2.(–5) – 20
= 4.(-5)2 + 2.(-5) - (-4)(-5)
= (-5).[4.(-5) + 2 - (-4)]
= (-5).[-20 + 2 + 4]
=(-5).(-14)
=70
a)125.(-24)+24.225
=(-125).24+24.225
=24.[(-125)+225]
=24.100
=2400
Các câu khác bạn làm tương tự nha
a ) \(125\times\left(-24\right)+24\times225\)
\(=24\left[\left(-125\right)+225\right]\)
\(=24\times100\)
\(=2400\)
b ) \(26\times\left(-125\right)-125\times\left(-36\right)\)
\(=125\left[\left(-26\right)-\left(-36\right)\right]\)
\(=125\times10\)
\(=1250\)
\(\frac{3}{5}\times\frac{6}{7}+\frac{3}{5}:7+\frac{6}{5}\)
\(=\frac{3}{5}\times\frac{6}{7}+\frac{3}{5}\times\frac{1}{7}+\frac{6}{5}\)
\(=\frac{3}{5}\times\left(\frac{6}{7}+\frac{1}{7}\right)+\frac{6}{5}\)
\(=\frac{3}{5}\times1+\frac{6}{5}\)
\(=\frac{3}{5}+\frac{6}{5}=\frac{9}{5}\)
~ Hok tốt ~
\(\frac{29}{12}:\frac{1}{2}-\frac{5}{12}:\frac{1}{2}-\frac{1}{2}\)
\(=\left(\frac{29}{12}-\frac{5}{12}\right):\frac{1}{2}-\frac{1}{2}\)
\(=2:\frac{1}{2}-\frac{1}{2}\)
\(=4-\frac{1}{2}=\frac{7}{2}\)
~ Hok tốt ~
a: \(=625-44\cdot12+\dfrac{41}{17}=97+\dfrac{41}{17}=\dfrac{1690}{17}\)
b: \(=-126-11^2+30=-126-121+30=-217\)