Tính:
1) A= {136-32. [25:25+17. 20160) :3 -3!]} : 102.52
2) B= 203-150 [(24- 92 : 32).23 +40] : (52.22) +23.6
3)C= {(125:52+15) - [120: (12.32+12)]} .13-22
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A=\(2^2-9^3+4^{-2}.16-2.5^2\)
\(=4-729+1-50=-774\)
B=\(\left(2^3.2\right).\dfrac{1}{2}+3^{-2}.3^2-7.1+5\)
\(B=2^4.\dfrac{1}{2}+1-7+5=8+1-7+5=7\)
C = 2-3 + (52)3.5-3 + 4-3.16 - 2.32 - 105.(\(\dfrac{24}{51}\))0
C = \(\dfrac{1}{8}\) + 56.5-3 + 4-3.42 - 2.9 - 105.1
C = \(\dfrac{1}{8}\) + 53 + \(\dfrac{1}{4}\) - 18 - 105
C = (\(\dfrac{1}{8}\) + \(\dfrac{1}{4}\)) - (105 - 125 + 18)
C = \(\dfrac{3}{8}\) - (-20 + 18)
C = \(\dfrac{3}{8}\) + 2
C = \(\dfrac{19}{8}\)
1*2*3*4*5*6*7*8*9*10*11*12*13*14*15*16*17*18*19*0*20*21*22*23*24*25*26*27*28*29*30*31*32=0
Bài 1: Thực hiện các phép tính sau:
\(a)\)Chưa rỏ đề
\(b)\)\(5025\div5-25\div5\)
\(=\)\(1005-5\)
\(=\)\(1000\)
\(c)\)\(218-180\div2\div9\)
\(=\)\(218-10\)
\(=\)\(208\)
\(d)\)\(\left(328-8\right)\div32\)
\(=\)\(320\div32\)
\(=\)\(10\)
Bài 1:
a) ( Tôi không nhìn rõ đầu bài )
b) 5025 : 5 - 25 : 5
= ( 5025 - 25 ) : 5
= 5000 : 5
= 1000
c) 218 - 180 : 2 : 9
= 218 - 180 : ( 2 . 9 )
= 218 - 180 : 18
= 218 - 10
= 208
d) ( 328 - 8 ) : 32
= 320 : 32
= 10
1) \(A=\left\{136-32.\left[\left(25:25+17.2016^0\right):3-3\right]\right\}:102.52\)
\(\Rightarrow A=\left\{136-32.\left[\left(1+17\right):3-3\right]\right\}:102.52\)
\(\Rightarrow A=\left[136-32.\left(18:3-3\right)\right]:102.52\)
\(\Rightarrow A=\left[136-32.\left(6-3\right)\right]:102.52\)
\(\Rightarrow A=\left(136-32.3\right):102.52\)
\(\Rightarrow A=\left(136-96\right):102.52\)
\(\Rightarrow A=40:102.52\)
\(\Rightarrow A=\dfrac{20}{51}.52\)
\(\Rightarrow A=\dfrac{1040}{51}\)