a) \(4^x\)=64
b) 35⋮ x
c) 135- ( x-5)= 105:3
d) x ⋮ 25 và x <100
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a: 2x(x+1)-135=-200
=>2(x^2+x)=-65
=>2x^2+2x+65=0
=>x^2+x+32,5=0
=>x^2+x+0,25+32,25=0
=>(x+0,5)^2+32,25=0(vô lý)
b: 4x-5(x-1)+15=13
=>4x-5x+5=-2
=>5-x=-2
=>x=5+2=7
c: 2/3x-1/4=3/5-7/8
=>2/3x=3/5-7/8+1/4=24/40-35/40+10/40=-1/40
=>x=-1/40:2/3=-1/40*3/2=-3/80
d: 1/2(2x-3)+105/2=-137/2
=>1/2(2x-3)=-137/2-105/2=-242/2=-121
=>2x-3=-242
=>2x=-239
=>x=-239/2
a/ 2130-(x+130)+72=-64
\(2130-\left(x+130\right)=-64-72\) \(2130-\left(x+130\right)=-136\)\(x+130=2130+136\)\(x+130=2266\)\(x=2266-130\)\(x=2136\)vậy x=2136
a/ 2130-(x+130)+72=-64
<=> -x-130+72+2130=-64
<=> x=2130+72-130+64=2136
b/135-|9-x|=35
<=> |9-x|=135-35=100
<=> \(\left[\begin{array}{nghiempt}9-x=100\\9-x=-100\end{array}\right.\)
<=>\(\left[\begin{array}{nghiempt}x=-91\\x=109\end{array}\right.\)
c/10-|x+3|=-4-(-10)
<=> |x+3|=10+4+(-10)
<=>|x+3|=4
<=>\(\left[\begin{array}{nghiempt}x+3=4\\x+3=-4\end{array}\right.\)
<=>\(\left[\begin{array}{nghiempt}x=1\\x=-7\end{array}\right.\)
a. 64 x 25 + 35 x 25 + 25
= 64 x 25 + 35 x 25 + 25 x 1
= 25 x ( 64 + 35 + 1 )
= 25 x 100
= 2500
b. 58 x 42 + 32 x 8 + 5 x 16
c. ( 42 x 43 + 57 x 43 + 43 ) - 360 : 4
= 42 x 43 + 57 x 43 + 43 x 1 - 90
= 43 x ( 42 + 57 +1 ) - 90
= 43 x 100 - 90
= 4300 - 90
= 4210
d. 456 : 2 x 181456 : 3 - 102
Trả lời:
a,\(64\times25+35\times25+25\)
\(=25\times\left(64+35+1\right)\)
\(=25\times100\)
\(=2500\)
b,\(58\times42+32\times8+5\times16\)
\(=2436+256+80\)
\(=2772\)
c,\(\left(42\times43+57\times43+43\right)-360\div4\)
\(=43\times\left(42+57+1\right)-90\)
\(=43\times100-90\)
\(=4300-90\)
\(=4210\)
d,\(456\div2\times181456\div3-102\)
\(=228\div3\times181456-102\)
\(=76\times181456-102\)
\(=13790656-102\)
\(=13790554\)
a) 135 - 5 (x + 4) = 35
5(x+4)=135-35
5(x+4)=100
x+4=100:5
x+4=20
x=20-4
x=16
b)25 + 3 (x - 8) = 106
3 (x - 8)=106-25
3 (x - 8)=81
x-8=81:3
x-8=27
x=27+8
x=35
a,5(x+4)=135-35
5(x+4)=100
x+4=100:5
x+4=20
x=20-4
x=16
b,3(x-8)=106-25
3(x-8)=81
x-8=81:3
x-8=27
x=27+8
x=35
a, (-4) . (+125) . (-25) . 6 . (-8)
=[ (-4) . (-25) ] . [ (+125) . (-8) ] . 6
= 100 . (-1000) . 6
= -100 000 . 6
= -600 000
b, 122 . (-12345) + 12345 . (-78)
= 12345 . [ (-122) + (-78) ]
= 12345 . (-200)
= -2 469 000
\(135-5\cdot\left(x+4\right)=35\)
\(5\cdot\left(x+4\right)=135-35\)
\(5\cdot\left(x+4\right)=100\)
\(x+4=100:5\)
\(x+4=20\)
\(x=20-4\)
\(x=16\)
b) \(25+3\cdot\left(x-8\right)=106\)
\(3\cdot\left(x-8\right)=106-25\)
\(3\cdot\left(x-8\right)=81\)
\(x-8=81:3\)
\(x-8=27\)
\(x=27+8\)
\(x=35\)
c) \(3^2\cdot\left(x+4\right)-5^2=5\cdot2^2\)
\(9\cdot\left(x+4\right)-25=5\cdot4\)
\(9\cdot\left(x+4\right)-25=20\)
\(9\cdot\left(x+4\right)=20+25\)
\(9\cdot\left(x+4\right)=45\)
\(x+4=45:9\)
\(x+4=5\)
\(x=5-4\)
\(x=1\)
Chúc bạn học tốt!!!!!!!!!!!!!!!!!!!!
1/2×(2×x-3)+105/2=-137/2
1/2×(2×x-3)=-137/2-105/2
1/2×(2×x-3)=-242/2
2×x-3=-242/2:1/2
2×x-3=-242
2.x=(-242)+3
2.x=239
x=239:2
x=239/2
A,-12×25-25×75-25×13
=[(-12)-75-13].25
=(-100).25
-2500
B,-50/7×49/10-35/2×-10/7+ -25/3× -9/5
=(-35)-(-25)+(-13)
=-23
C,-354+265-156+125
=[(-354)-156]+(265+125)
=(-510)+277
=-233
D,-74+40-50+16-35
=(-74)+40+(-50)+16+(-35)
=[(-74)+(-35)]+[40+(-50)+16]
=(-109)+26
=-83
E,-2/3×4/5+-4/5×4/3-0,125
=-2/3.4/5+4/5.(-4/3)-0,125
=4/5.[-2/3+(-4/3)]-0,125
=4/5.(-2)-0,125
=-8/5-0,125
=(-1,6)+(-0,125)
=-1,725
a/ x - ( 25 - x) = x - 15
=> x - 25 + x = x - 15
=> 2x - x = -15 + 25
=> x = 10
b/ x - 8 = -13 - 8
=> x = -13 - 8 + 8 = -13
c/ x - (-15) = 5 - (-19)
=> x + 15 = 5 + 19 => x = 5 + 19 - 15 = 9
d/ (x + 35) = 2x + 15 + (13 - 4)
=> x + 35 = 2x + 15 + 13 - 4
=> x - 2x = 15 + 13 - 4 - 35
=> -x = -11 => x = 11
e/ 5 - 2x = 15-(-9) - 3x
=> 5 - 2x = 15 + 9 - 3x
=> -2x + 3x = 15 + 9 - 5
=> x = 19
g/ x + 135 = 3x - 15
=> x - 3x = -15 - 135
=> -2x = -150
=> x = -150/ - 2 = 75
a) \(4^{x^{ }}=64\)
\(\Rightarrow4^x=4^3\)
\(\Rightarrow x=3.\)
b) Vì \(35⋮x\)
\(\Rightarrow x\inƯ\left(35\right)=\left\{1;5;7;35\right\}\)
Vậy \(x\in\left\{1;5;7;35\right\}\)
c) \(135-\left(x-5\right)=105:3\)
\(\Leftrightarrow\)\(135-\left(x-5\right)=35\)
\(\Leftrightarrow x-5=135-35\)
\(\Leftrightarrow x-5=100\)
\(\Leftrightarrow x=100+5\)
\(\Leftrightarrow\) \(x=105.\)
d) Vì \(x⋮25\)
\(\Rightarrow x\in B\left(25\right)=\left\{0;25;50;75;100;...\right\}\)
Mà \(x< 100\)
\(\Rightarrow x\in\left\{0;25;50;75\right\}\)