2x3 + 3x - 8x + 3 = 0
Mong các acj giúp em vs ạ, e đang cần gấp
E cảm ơn ạ.../
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
NT
3
Những câu hỏi liên quan
3 tháng 5 2021
Để khôi phục trạng thái cũ văn bản ta nhấn phím: Undo
DM
3 tháng 5 2021
Để khôi phục trạng thái cũ văn bản ta nhấn phím Undo ( hoặc Ctrl + Z )
LN
2
LN
0
HN
1
K
7 tháng 3 2021
8. As it is raining heavily, we can't go on a picnic
9. I suggest (that) you should get a plumber to check the pipes
10. If you don't succeed, you'll have to try it again
11. If she had enough money, she would buy the dictionary
12. I suggest using gas instead of burning coal
13. I suggest you should install a burglar alarm in your house
14. If we recycle, we will save natural resources
15. If you don't hurry up, you will be late for work
16. If you work too much, you will be tired
17. I suggest putting different kinds of.....
18. Lan broke the glass as she was careless
19. If you litter the place around you, it will be a junk yard
20. Paul suggested using public transportation
21. If she doesn't reduce the use of water and electricity, she will have to.....
22. Since the weather was snowy, we postponed our soccer match
23. Tan suggested that Lam should buy a car
24. Lan suggested that I should look for another job
25. The scientist suggested using public transportation instead of private vehicles
26. giống c12
27. The principle is pleased that the students in grade 9 are good helpers
28. If we put garbage into the bins, we will minimize pollution
29. If you are careless, you will broke the vase
30. If you don't stop cutting trees, I will call the police
31. If you use electricity to catch fish, you will be fined heavily
32. I'm sure that that boy will have a test.....
33. We are disappointed that you threw the rubbish on the street
34. It is extremely important that all of us work together to protect the environment
35. I'm sorry that I couldn't do anything to help you
36. He is sure that environmental pollution in this area can be controlled
37. She was annoyed that he damaged the car yesterday
4 tháng 5 2021
Câu 29:
a) nFe= 11,2/56=0,2(mol
nH2SO4=24,5/98=0,25(mol)
PTHH: Fe + H2SO4 -> FeSO4 + H2
Ta có: 0,2/1 < 0,25/1
=> nFe hết, nH2SO4 dư, tính theo nFe.
nH2SO4(p.ứ)=nH2=nFe=0,2(mol)
=>nH2SO4(dư)=nH2SO4(ban đầu) - nH2SO4(p.ứ)=0,25-0,2=0,05(mol)
=>mH2SO4(dư)=0,05.98=4,9(g)
b) V(H2,đktc)=0,2.22,4=4,48(l)
4 tháng 5 2021
Câu 28:
-Cho quỳ tím nhận biết:+Quỳ tím chuyển đỏ:H2SO4
+Quỳ tím chuyển xanh:Ca(OH)2
+Quỳ tím không chuyển màu:NaNO3
Câu 29:
Fe+H2SO4--->FeSO4+H2
Theo PT: 1 1 1 1 mol
Theo đề bài:11,2 24,5 g
Xét tỉ lệ:11,2/1 24,5/1=> cái nào nhiều hơn thì cái đó dư nhá.
b, Tính H2 theo chất theo cái ko dư(Fe)
H9
HT.Phong (9A5)
CTVHS
7 tháng 12 2023
Bài 3:
a) \(159-\left(25-x\right)=43\)
\(\Rightarrow25-x=159-43\)
\(\Rightarrow25-x=116\)
\(\Rightarrow x=25-116\)
\(\Rightarrow x=-91\)
b) \(\left(79-x\right)-43=-\left(17-52\right)\)
\(\Rightarrow\left(79-x\right)-43=-\left(-35\right)\)
\(\Rightarrow79-x=35+43\)
\(\Rightarrow79-x=78\)
\(\Rightarrow x=79-78\)
\(\Rightarrow x=1\)
c) \(-\left(-x+13-142\right)+18=55\)
\(\Rightarrow-\left(-x+13-142\right)=55-18\)
\(\Rightarrow x-13+142=37\)
\(\Rightarrow x+129=37\)
\(\Rightarrow x=37-129\)
\(\Rightarrow x=-92\)
\(<=>2x^2-5x+3=0\)
<=>\(2x^2-2x-3x+3=0\)
\(<=>2x(x-1)-3(x-1)=0\)
\(<=>(2x-3)(x-1)=0\)
th1 \(2x-3=0<=>x=3/2\)
th2 \(X-1=0<=>x=1\)
pt có tập nghiệm S={3/2;1}
\(2x^3+3x^2-8x+3=0\\ \Rightarrow\left(2x^3-2x^2\right)+\left(5x^2-5x\right)-\left(3x-3\right)=0\\ \Rightarrow2x^2\left(x-1\right)+5x\left(x-1\right)-3\left(x-1\right)=0\\ \Rightarrow\left(x-1\right)\left(2x^2+5x-3\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-1=0\\2x^2+5x-3=0\end{matrix}\right.\)
\(x-1=0\\ \Rightarrow x=1\)
\(2x^2+5x-3=0\\ \Rightarrow\left(2x^2+6x\right)-\left(x+3\right)=0\\ \Rightarrow2x\left(x+3\right)-\left(x+3\right)=0\\ \Rightarrow\left(x+3\right)\left(2x-1\right)=0\\ \Rightarrow\left[{}\begin{matrix}x+3=0\\2x-1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-3\\x=\dfrac{1}{2}\end{matrix}\right.\)
Vậy \(x=\left\{-3;\dfrac{1}{2};1\right\}\)