Question

[Nguyễn Lương Nguyên]

Cho \(\dfrac{a}{b}\)=\(\dfrac{c}{d}\) chứng minh rằng:

a) \(\dfrac{a}{a-b}\)=\(\dfrac{c}{c-d}\)

b) \(\dfrac{a}{b}\)=\(\dfrac{a+c}{b+d}\)

c)\(\dfrac{a}{3a+b}\)=\(\dfrac{c}{3c+b}\)

d) \(\dfrac{a.c}{b.c}\)=\(\dfrac{a^2+c^2}{b^2+d^2}\)

e) \(\dfrac{a.b}{c.d}\)=\(\dfrac{a^2-b^2}{c^2-d^2}\)

f) \(\dfrac{a.b}{c.d}\)=\(\dfrac{\left(a-b\right)^2}{\left(c-d\right)^2}\)

Answer 1

[Đạt Trần Tiến]

Ta có \(\frac{a}{b}=\frac{c}{d}=>\frac{a}{c}=\frac{b}{d}=\frac{a-b}{c-d}=>\frac{a}{a-b}=\frac{c}{c-d} \)

Answer 2

[Nguyễn Lương Nguyên]

còn mấy con kia nữa bn.... Giúp cái...