Question

[Mộc Lung Hoa]

Quy đồng mẫu thức các phân thức:

a,\(\dfrac{2x}{x^2-8x+16}\),\(\dfrac{x}{3x^2-12x}\)

Answer 1

[Heo Trang]

x²-8x+16=(x+4)²

3x²-12x=3x(x-4)

MTC: 3x(x-4)²

\(\dfrac{2x}{x^2-8x+16}=\dfrac{2x}{\left(x-4\right)^2}=\dfrac{2x.3x}{\left(x-4\right)^2.3x}=\dfrac{6x^2}{3x\left(x-4\right)^2}\)

\(\dfrac{x}{3x^2-12x}=\dfrac{x}{3x\left(x-4\right)}=\dfrac{x.\left(x-4\right)}{3x\left(x-4\right)\left(x-4\right)}\)