1. xác định a,b,c,d
a) \(\dfrac{10x-4}{x^3-4x}\) = \(\dfrac{a}{x}+\dfrac{b}{x-2}+\dfrac{c}{x+2}\)
b) \(\dfrac{1}{x^3-1}\) = \(\dfrac{a}{x-1}+\dfrac{bx+c}{x^2+x+1}\)
c) \(\dfrac{x^3+2x}{x^4-1}\) = \(\dfrac{a}{x+1}+\dfrac{b}{x-1}+\dfrac{cx+d}{x^2+1}\)
giúp mới ạ!!!