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c) (1253.75-1755/5) / 20012002
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d)123 x 456+456 x 321 - 256 x444
= ( 123 + 321) x456 - 256 x 444
= 444 x456 -256 x444
=200 x 444
=88800
\(=\left[\dfrac{9-3}{162}\cdot\dfrac{81}{17}+\dfrac{35}{34}\right]:\left(\dfrac{3}{5}+\dfrac{7}{102}\right)\cdot\dfrac{102}{5}+2017\)
\(=\left[\dfrac{6}{2}\cdot\dfrac{1}{17}+\dfrac{35}{34}\right]:\dfrac{341}{510}\cdot\dfrac{102}{5}+2017\)
\(=\dfrac{41}{34}\cdot\dfrac{510}{341}\cdot\dfrac{102}{5}+2017=\dfrac{12546}{341}+2017=\dfrac{700343}{341}\)
\(\left(125^3.7^5-175^5:5\right):2016^{2017}\)
= \(\left[\left(5^3\right)^3.7^5-\left(5^2.7\right)^5:5\right]:2016^{2017}\)
= \(\left[5^{3.3}.7^5-5^{2.5}.7^5:5\right]:2016^{2017}\)
= \(\left[5^9.7^5-5^{10}.7^5:5\right]:2016^{2017}\)
= \(\left[5^9.7^5-5^9.7^5\right]:2016^{2017}\)
= \(0:2016^{2017}\)
= \(0\)
\(\dfrac{125^3\cdot7^5-175^5:5}{2016^{2017}}\)
\(=\dfrac{5^9\cdot7^5-5^{10}\cdot7^5:5}{2016^{2017}}\)
\(=\dfrac{5^9\cdot7^5-5^9\cdot7^5}{2016^{2017}}\)
=0
c) Ta có: \(\left(\dfrac{6-2\sqrt{2}}{3-\sqrt{2}}-\dfrac{5}{\sqrt{5}}\right)\cdot\dfrac{1}{2-\sqrt{5}}\)
\(=\left(\dfrac{2\left(3-\sqrt{2}\right)}{3-\sqrt{2}}-\sqrt{5}\cdot\dfrac{\sqrt{5}}{\sqrt{5}}\right)\cdot\dfrac{1}{2-\sqrt{5}}\)
\(=\left(2-\sqrt{5}\right)\cdot\dfrac{1}{2-\sqrt{5}}\)
=1
d) Ta có: \(\sqrt{\left(2-\sqrt{5}\right)^2}-\sqrt{5}\)
\(=\sqrt{5}-2-\sqrt{5}\)
=-2