(3x - 5)^4 = 256
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\(\left(\frac{-3}{4}\right)^{3x+5}=\left(\frac{81}{256}\right)^{-1}\)
\(\Rightarrow\left(\frac{-3}{4}\right)^{3x+5}=\frac{256}{81}\)
\(\Rightarrow\left(\frac{-3}{4}\right)^{3x+5}=\left(\frac{-3}{4}\right)^{-4}\)
\(\Rightarrow3x+5=-4\)
\(\Rightarrow3x=-9\)
\(\Rightarrow x=-3\)
Vậy x= -3
a: =>2x+5=4
=>2x=-1
hay x=-1/2
b: \(\Leftrightarrow\left(3x-4\right)^2\cdot\left[\left(3x-4\right)^2-1\right]=0\)
=>(3x-4)(3x-5)(3x-3)=0
hay \(x\in\left\{1;\dfrac{4}{3};\dfrac{5}{3}\right\}\)
c: \(\Leftrightarrow3^{x+1}=3^{2x}\)
=>2x=x+1
=>x=1
d: \(\Leftrightarrow2^{2x+3}=2^{2x-10}\)
=>2x+3=2x-10
=>0x=-13(vô lý)
\(\left(5-7x\right)-\left(9-3x\right)=256\)
\(5-7x-9+3x=256\)
\(\left(5-9\right)-\left(7x-3x\right)=256\)
\(-4-4x=256\)
\(4x=-4-256\)
\(4x=-4+-256\)
\(4x=-260\)
\(x=-60\)
5 - 7x - 9 + 3x = 256
(5 - 9) - (7x - 3x) = 256
-4 - 4x = 256
4x = -4 - 256
4x = -260
x = -260 : 4
x = -65
Vậy x = -65
a) Ta có : 2 x : 2 2 = 2 5 nên x = 7.
b) Ta có: 3 x : 3 2 = 3 5 nên x = 7.
c) Ta có : 4 4 : 4 x = 4 2 nên x = 2.
d) Ta có : 5 x : 5 2 = 5 2 nên x = 4,
e) Ta có: 5 x + 1 : 5 = 5 4 nên x = 4.
f) Ta có : 4 2 x - 1 : 4 = 4 2 nên x = 2
a.\(3x^2-51=-24\)
\(\Rightarrow3x^2=27\)
\(\Rightarrow x^2=9\)
\(\Rightarrow x=3\)
b.\(5x.\left(5^3\right)^2=625\)
\(\Rightarrow5x=5^5:5^{\left(3x2\right)}\)
\(\Rightarrow5x=5^5:5^6\)
\(\Rightarrow5x=5^{-1}=0,2\)
\(\Rightarrow x=0,2:5\)
\(\Rightarrow x=0,04\)
\(\left(3x-5\right)^4=256\)
\(\Leftrightarrow\left[{}\begin{matrix}3x-5=4\\3x-5=-4\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{1}{3}\end{matrix}\right.\)
Ta có: \(\left(3x-5\right)^4=256\)
\(\Leftrightarrow\left[{}\begin{matrix}3x-5=-4\\3x-5=4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=3\end{matrix}\right.\)