Tính nhanh: 2.19.6 + 3.37.4+44.12
mn nhanh nhé
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Câu A là :2x19x6+3x37x4+44x12=228+444+528=1200
Câu B là:18x15+35+15x32+35x49=270+35+480+1715=(1715+35)+(270+480)=1750+750=1500
2.19.6 + 3.37.4 + 44.12
= 12 .19 + 12.37 + 44.12
= 12.(19+37+44)
= 12.100 = 1200
2.9.6+3.37.4+44.12
=2.6.9+3.4.37+44.12
=12.9+12.37+44.12
=12. (9+37+44)
=12.90
=1080
2.9.6+3.37.4+44.12
=2.3.3.3.2+3.37.4+44.4.3
=4.3.3.3+3.4.37+44.3.4
=3.4.(3.3+37+44)
=12.80
=960
\(A=\dfrac{5}{4x7}+\dfrac{5}{7x10}+...+\dfrac{5}{25x28}+\dfrac{5}{28x31}\)
\(\dfrac{3}{5}A=\dfrac{7-4}{4x7}+\dfrac{10-7}{7x10}+...+\dfrac{28-25}{25x28}+\dfrac{31-28}{28x31}\)
\(\dfrac{3}{5}A=\dfrac{7}{4x7}-\dfrac{4}{4x7}+\dfrac{10}{7x10}-\dfrac{7}{7x10}+...+\dfrac{28}{25x28}-\dfrac{25}{25x28}+\dfrac{31}{28x31}-\dfrac{28}{28x31}\)
\(\dfrac{3}{5}A=\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+...+\dfrac{1}{25}-\dfrac{1}{28}+\dfrac{1}{28}-\dfrac{1}{31}\)
\(\dfrac{3}{5}A=\dfrac{1}{4}-\dfrac{1}{31}=\dfrac{27}{124}\)
\(A=\dfrac{27}{124}:\dfrac{3}{5}=\dfrac{27}{124}x\dfrac{5}{3}=\dfrac{45}{124}\)
A = \(\dfrac{1\times2\times3\times4\times5\times6\times....\times100\times101}{3\times4\times5\times6\times.......\times100}\)
A = 1 x 2 x 101 x \(\dfrac{3\times4\times5\times6\times........\times100}{3\times4\times5\times6.............\times100}\)
A = 1 x 2 x 101 x 1
A = 202
\(\dfrac{1.2.3.4.5....101}{3.4.5.6.100}\)
Ta thấy phần tử sẽ triệt tiêu hết cho mẫu nên mẫu sẽ bằng 1
=> \(\dfrac{2.101}{2}=202\)
\(15.14.12.25.2=15.14.\left(4.3\right).25.2\)
\(=15.2.25.4.14.3=30.100.42\)
\(=3000.42=126000\)
#Hok_tốt
\(15\cdot14\cdot12\cdot25\cdot2\)
\(=3\cdot5\cdot2\cdot7\cdot3\cdot4\cdot25\cdot2\)
\(=\left(3\cdot3\right)\cdot\left(5\cdot2\right)\cdot\left(4\cdot25\right)\cdot2\cdot7\)
\(=9\cdot10\cdot100\cdot2\cdot7\)
\(=9000\cdot2\cdot7\)
\(=18000\cdot7\)
\(=126000\)
2.19.6 + 3.37.4+44.12=12.19+12.37+44.12=12(19+37+44)=12.100=1200
2.19.6+3.37.4+44.12
=2.6.19+3.4.37+12.44
=12.19+12.37+12.44
=12.(19+37+44)
=12.100
=1200