\(\dfrac{x+5}{-12}\)=\(\dfrac{-12}{x+5}\)
Help me! Thank you!
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
DN
3
22 tháng 4 2017
Ta có: \(\left|\dfrac{1}{4}+x\right|=\dfrac{5}{6}\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{4}+x=\dfrac{5}{6}\\\dfrac{1}{4}+x=\dfrac{-5}{6}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{6}-\dfrac{1}{4}\\x=\dfrac{-5}{6}-\dfrac{1}{4}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{10}{12}-\dfrac{3}{12}\\x=\dfrac{-10}{12}-\dfrac{3}{12}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{7}{12}\\x=\dfrac{-13}{12}\end{matrix}\right.\)
Vậy \(x=\dfrac{7}{12}\) hoặc \(x=-\dfrac{13}{12}\)
21 tháng 10 2018
=> (\(^{4^4}\) -\(^x\) ).5=3.(\(^x\) -12)
=>(256-x).5=3.(x-12)
=> 1280-5x=3x-36
=> 1280 +36= 3x+5x
=> 1316= 8x
=> x= 1316:8
=> x =164,5
DB
1
23 tháng 6 2022
\(\Leftrightarrow\left(19.75\right):x=\left(\dfrac{33}{5}-\dfrac{51}{16}\right)\cdot\dfrac{35}{6}:\dfrac{5}{2}\)
\(\Leftrightarrow19.75:x=\dfrac{637}{80}\)
hay x=1580/637
L
19 tháng 12 2021
= \(\dfrac{6x}{x-2}+\dfrac{-12}{x-2}\) = \(\dfrac{6x-12}{x-2}=\dfrac{6\left(x-2\right)}{x-2}=6\)
NM
3
10 tháng 8 2023
\(\left(x-\dfrac{1}{2}\right)^2-\dfrac{1}{3}=\dfrac{23}{12}\\ \Rightarrow\left(x-\dfrac{1}{2}\right)^2=\dfrac{23}{12}+\dfrac{1}{3}=\dfrac{9}{4}\\ \Rightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=\dfrac{3}{2}\\x-\dfrac{1}{2}=-\dfrac{3}{2}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}+\dfrac{1}{2}=2\\x=-\dfrac{3}{2}+\dfrac{1}{2}=-1\end{matrix}\right.\)
10 tháng 8 2023
\(\left(x-\dfrac{1}{2}\right)^2-\dfrac{1}{3}=\dfrac{23}{12}\)
\(\Rightarrow\left(x-\dfrac{1}{2}\right)^2=\dfrac{23}{12}+\dfrac{1}{3}\)
\(\Rightarrow\left(x-\dfrac{1}{2}\right)^2=\dfrac{9}{4}=\left(\dfrac{3}{2}\right)^2\)
\(\Rightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=\dfrac{3}{2}\\x-\dfrac{1}{2}=-\dfrac{3}{2}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-1\end{matrix}\right.\)
21 tháng 8 2023
\(\dfrac{4}{3.5}+\dfrac{8}{5.9}+\dfrac{12}{9.15}+...+\dfrac{32}{x\left(x+16\right)}=\dfrac{16}{15}\)
\(2.\left(\dfrac{2}{3.5}+\dfrac{4}{5.9}+\dfrac{6}{9.15}+..+\dfrac{16}{X.\left(X+16\right)}\right)=\dfrac{16}{15}\)
\(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{15}+...+\dfrac{1}{X}-\dfrac{1}{X+16}=\dfrac{8}{15}\)
\(\dfrac{1}{X+16}=\dfrac{1}{3}-\dfrac{8}{15}\)
\(\dfrac{1}{X+16}=\dfrac{-1}{5}\)
\(X+16=-5\)
\(X=-21\)
Tìm x biết :
\(\dfrac{x+5}{-12}\) = \(\dfrac{-12}{x+5}\)
=> (x+5) . (x+5) = (-12) . (-12)
=> x + 5 = 12 hoặc x + 5 = -12
*Nếu x +5 = 12 => x = 7
*Nếu x + = -12 => x = -17
Vậy x = 7 hoặc x= -17