tính
2-7/9-5/6 1-1/3-1/6-1/12-1/24
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1 / 9 + 2 / 9 + 4 / 9 = 7 / 9
5 / 5 + 6 / 5 + 1 = 15 / 5 = 3
12 / 2 + 4 / 2 + 1 + 3 / 2 = 21 / 2
7 / 3 + 6 / 3 + 1 + 1 = 19 / 3
a, \(\dfrac{1}{2}\) - ( - \(\dfrac{1}{3}\) ) + \(\dfrac{1}{23}\) + \(\dfrac{1}{6}\)
= \(\dfrac{5}{6}\) + \(\dfrac{1}{23}\) + \(\dfrac{1}{6}\)
= 1 + \(\dfrac{1}{23}\)
= \(\dfrac{24}{23}\)
b, \(\dfrac{11}{24}\) - \(\dfrac{5}{41}\) + \(\dfrac{13}{24}\) + 0,5 - \(\dfrac{36}{41}\)
= (\(\dfrac{11}{24}\) + \(\dfrac{13}{24}\)) - ( \(\dfrac{5}{41}\) + \(\dfrac{36}{41}\)) + 0,5
= 1 - 1 + 0,5
= 0,5
c,\(-\dfrac{1}{12}-\left(\dfrac{1}{6}-\dfrac{1}{4}\right)\)
=\(-\dfrac{1}{12}-\left(-\dfrac{1}{12}\right)\)
=0
d, \(\dfrac{1}{6}-\left[\dfrac{1}{6}-\left(\dfrac{1}{4}+\dfrac{9}{12}\right)\right]\)
= \(\dfrac{1}{6}-\left[\dfrac{1}{6}-1\right]\)
= \(\dfrac{1}{6}-\left(-\dfrac{5}{6}\right)\)
= 1
1+2-3-4+5+6-7-8+9+................+33
=1+(2-3-4+5)+(6-7-8+9)+............+(30-31-32+33)
=1+0+0+..............+0
=1
bài 4:so sánh
5/2 lớn hơn 3/7
4/3 lớn hơn,3/2 lớn hơn
bài 6:rút gọn các phân số sau:
3/9=1/3 9/12=3/4 8/18=4/9 60/36=10/6 17/34=1/2 17/51=1/3 35/100=7/20 25/100=1/4 8/1000=1/125 24/30=4/5 18/54=1/3 72/42=12/7
đay nhé mk chưa làm hết đc bn viết liền quá mk nhìn khó mà mk hỏi bài 7 là nhân hay cộng vậy?
\(\dfrac{9}{10}+\dfrac{3}{5}\times\dfrac{1}{6}=\dfrac{9}{10}+\dfrac{3}{30}=\dfrac{27}{30}+\dfrac{3}{30}=1\)
\(\dfrac{31}{12}-\dfrac{7}{5}:\dfrac{14}{15}=\dfrac{31}{12}-\dfrac{7}{5}\times\dfrac{15}{14}=\dfrac{31}{12}-\dfrac{3}{2}=\dfrac{31}{12}-\dfrac{18}{12}=\dfrac{13}{12}\)
\(\dfrac{4}{7}\times\dfrac{2}{5}:\dfrac{10}{9}=\dfrac{14}{35}\times\dfrac{9}{10}=\dfrac{9}{25}\)
Câu 1:
\(\dfrac{3}{5}-\dfrac{5}{6}=\dfrac{18}{30}-\dfrac{25}{30}=\dfrac{18-25}{30}=\dfrac{-7}{30}\)
Câu 2:
\(\dfrac{-5}{9}-\dfrac{-5}{12}=\dfrac{-20}{36}-\dfrac{-15}{36}=\dfrac{-20-\left(-15\right)}{36}=\dfrac{-5}{36}\)
1. 3/5-5/6=-7/30
2.\(\dfrac{-5}{9}-\dfrac{-5}{12}=\dfrac{-5}{36}\)
\(1-\frac{1}{3}-\frac{1}{6}-\frac{1}{12}-\frac{1}{24}\)
\(=1-\frac{8}{24}-\frac{4}{24}-\frac{2}{24}-\frac{1}{24}\)
\(=\frac{24}{24}-\frac{8}{24}-\frac{4}{24}-\frac{2}{24}-\frac{1}{24}\)
\(=\frac{24-8-4-2-1}{24}\)
\(=\frac{9}{24}\)
\(=\frac{3}{8}\)
Dấu '/' là dấu chia ak bn