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HT
a) \(\dfrac{3}{4}+\dfrac{9}{5}\div\dfrac{3}{2}-1=\dfrac{3}{4}+\dfrac{18}{15}-1=\dfrac{39}{20}-1=\dfrac{19}{20}\)
b) \(\dfrac{6}{7}\cdot\dfrac{8}{13}+\dfrac{6}{13}\cdot\dfrac{9}{7}-\dfrac{4}{13}\cdot\dfrac{6}{7}=\dfrac{48}{91}+\dfrac{54}{91}-\dfrac{24}{91}=\dfrac{48+51-24}{91}=\dfrac{78}{91}=\dfrac{6}{7}\)
c) \(\dfrac{-3}{7}+\left(\dfrac{3}{-7}-\dfrac{3}{-5}\right)\)\(=\dfrac{-3}{7}+\left(\dfrac{-3}{7}-\dfrac{-3}{5}\right)=\dfrac{-3}{7}+\dfrac{6}{35}=-\dfrac{9}{35}\)
a: Xét tứ giác AEHF có
\(\widehat{AEH}=\widehat{AFH}=\widehat{FAE}=90^0\)
Do đó: AEHF là hình chữ nhật
ờ...tớ ko nhầm thì thừa are
nếu bỏ are thì she's making a papper boat
1 How long do you live in HN
2 How often did you go to the movies
3 What did Mrs Robinson buy
4 When was your father in Nghe An
5 How do they go to school
6 Why didn't she go to class
7 Who left home at 7o'clock yesterday
8 What subject does he study in the high school
9 What is your favorite hobby
10 How far is it
3. are there any eggs?-No, there aren't some
4.is there any salt?- yes, there is any
5.are there any carrots?-yes, there are some
6.are there any apples?-no there aren't some
7.is there any suger?-yes, there is any
8.are there any cakes?-no there aren't some
9.is there any butter?-no. there isn't any
10. is there any mineral water?- yes. there is any
b: Gọi giao của AH với BC là F
=>AH vuông góc BC tại F
góic CHI=góc AHD=90 độ-góc HAD=góc ABC=1/2*sđ cung AC
góc CIH=1/2*sđ cung CA
=>góc CHI=góc CIH
=>ΔCHI cân tại C
c:
góc BDC=góc BEC=90 độ
=>BDEC nội tiếp đường tròn đường kính BC
=>MD=ME
=>ΔMDE cân tại M
mà MN là trung tuyến
nên MN vuông góc DE
Kẻ tiếp tuyến Ax của (O)
=>góc xAC=góc ABC
=>góc xAC=góc AED
=>Ax//DE
=>DE vuông góc OA
=>MN//AO
Bài 5:
a: Ta có: \(\left|\dfrac{3}{5}-x\right|\ge0\forall x\)
\(\Leftrightarrow\left|\dfrac{3}{5}-x\right|+\dfrac{1}{9}\ge\dfrac{1}{9}\forall x\)
Dấu '=' xảy ra khi \(x=\dfrac{3}{5}\)
b: Ta có: \(\left|x-\dfrac{5}{6}\right|\ge0\forall x\)
\(\Leftrightarrow-\left|x-\dfrac{5}{6}\right|\le0\forall x\)
\(\Leftrightarrow-\left|x-\dfrac{5}{6}\right|+\dfrac{2011}{2012}\le\dfrac{2011}{2012}\forall x\)
Dấu '=' xảy ra khi \(x=\dfrac{5}{6}\)
Bài 4:
a: Ta có: \(\left|x-\dfrac{1}{3}\right|+4=6\)
\(\Leftrightarrow\left|x-\dfrac{1}{3}\right|=2\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{3}=2\\x-\dfrac{1}{3}=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{3}\\x=-\dfrac{5}{3}\end{matrix}\right.\)
b: Ta có: \(\left|5.6-x\right|=4.6\)
\(\Leftrightarrow\left[{}\begin{matrix}5.6-x=4.6\\5.6-x=-4.6\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=10.2\end{matrix}\right.\)
c: Ta có: \(\left|x\right|+x=\dfrac{2}{3}\)
\(\Leftrightarrow\left|x\right|=\dfrac{2}{3}-x\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}-x\left(x\ge0\right)\\-x=\dfrac{2}{3}-x\left(x< 0\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=\dfrac{2}{3}\\0x=\dfrac{2}{3}\left(loại\right)\end{matrix}\right.\Leftrightarrow x=\dfrac{1}{3}\left(nhận\right)\)