5 phần 9× 14 phần 17+ 1 phần 17× 5 phần 9+ 2 phần 9× 5 phần 17
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VV
2
22 tháng 7 2017
\(\left(2^2:\frac{1}{2}\right).\frac{1}{8}+\frac{9}{3^2}-7.\left(\frac{14}{17}\right)+5\)
=\(2.\frac{1}{8}+\frac{1}{3}-\frac{98}{17}+5\)
=\(\frac{1}{4}+\frac{1}{3}-\frac{98}{17}+5\)
=\(\frac{-37}{204}\)
10 tháng 2 2019
\(\frac{17}{33}.\frac{2}{5}+\frac{3}{5}.\frac{17}{33}-\frac{17}{33}\)
\(=\frac{17}{33}\times\frac{2}{5}+\frac{3}{5}\times\frac{17}{33}-\frac{17}{33}\times1\)
\(=\frac{17}{33}\times\left(\frac{2}{5}+\frac{3}{5}-1\right)\)
\(=\frac{17}{33}\times\left(1-1\right)\)
\(=\frac{17}{33}\times0=\frac{17}{33}\)
KN
12 tháng 4 2018
A) cách 1\(\frac{9}{5}:\frac{17}{15}+\frac{8}{5}:\frac{17}{15}\)
\(=\frac{9}{5}\cdot\frac{15}{17}+\frac{8}{5}\cdot\frac{15}{17}\)
\(=\frac{135}{85}+\frac{120}{85}\)
\(=\frac{255}{85}\)
\(=3\)
Cách 2\(\frac{9}{5}:\frac{17}{15}+\frac{8}{5}:\frac{17}{15}\)
\(=\frac{9}{5}\cdot\frac{15}{17}+\frac{8}{5}\cdot\frac{15}{17}\)
\(=\frac{15}{17}\cdot\left(\frac{9}{5}+\frac{8}{5}\right)\)
=\(\frac{15}{17}\cdot\frac{17}{5}\)
\(=\frac{15\cdot17}{17\cdot5}\)
\(=\frac{5\cdot3\cdot17}{17\cdot5}\)
\(=3\)
B) Cách 1 :
0,9 : 0,25 + 1,05 : 0,25
= 3,6 + 4,2
=7,8
Cách 2:
0,9 : 0,25 + 1,05 : 0,25
\(=0,9:\frac{1}{4}+1,05:\frac{1}{4}\)
\(=0,9\cdot4+1,05\cdot4\)
\(=4\cdot\left(0,9+1,05\right)\)
\(=4\cdot1,95\)
=\(7,8\)
10 tháng 5 2020
a, \(\frac{3}{5}+\frac{-4}{15}=\frac{9}{15}-\frac{4}{15}=\frac{5}{15}=\frac{1}{3}\)
b, \(\frac{-1}{3}+\frac{2}{5}+\frac{2}{15}=\frac{-5}{15}+\frac{6}{15}+\frac{2}{15}=\frac{3}{15}=\frac{1}{5}\)
c, \(\frac{-3}{5}+\frac{7}{21}+\frac{-4}{5}+\frac{7}{5}=\frac{-3}{5}+\frac{1}{3}+\frac{-4}{5}+\frac{7}{5}=\left(\frac{-3}{5}+\frac{-4}{5}+\frac{7}{5}\right)+\frac{1}{3}=\frac{1}{3}\)
d, \(\frac{2}{7}+\frac{1}{9}+\frac{3}{7}+\frac{5}{9}+\frac{-5}{6}=\left(\frac{2}{7}+\frac{3}{7}\right)+\left(\frac{1}{9}+\frac{5}{9}\right)+\frac{-5}{6}=\frac{5}{7}+\frac{6}{9}+\frac{-5}{6}=\frac{90}{126}+\frac{84}{126}+\frac{-105}{126}=\frac{69}{126}=\frac{23}{42}\)
e, \(\frac{-5}{7}+\frac{3}{4}+\frac{-1}{5}+\frac{-2}{7}+\frac{1}{4}=\left(\frac{-5}{7}+\frac{-2}{7}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)+\frac{-1}{5}=\left(-1\right)+1+\frac{-1}{5}=\frac{-1}{5}\)
f, \(\frac{-3}{31}+\frac{-6}{17}+\frac{1}{25}+\frac{-28}{31}+\frac{-1}{17}+\frac{-1}{5}=\left(\frac{-3}{31}+\frac{-28}{31}\right)+\left(\frac{-6}{17}+\frac{-1}{17}\right)+\left(\frac{1}{25}+\frac{-1}{5}\right)=\left(-1\right)+\frac{-7}{17}+\frac{-4}{25}=\frac{-425}{425}+\frac{-175}{425}+\frac{-68}{425}=\frac{-668}{425}\)
Chúc bn học tốt
DV
3
TD
16 tháng 8 2021
\(\frac{5}{9}\times\frac{8}{17}+\frac{4}{9}\times\frac{8}{17}\)
\(=\left(\frac{5}{9}+\frac{4}{9}\right)\times\frac{8}{17}\)
\(=1\times\frac{8}{17}\)
\(=\frac{8}{17}\)
\(\dfrac{5}{9}\cdot\dfrac{14}{17}+\dfrac{1}{17}\cdot\dfrac{5}{9}+\dfrac{2}{9}\cdot\dfrac{5}{17}\\ =\dfrac{5}{9}\cdot\dfrac{14}{17}+\dfrac{1}{17}\cdot\dfrac{5}{9}+\dfrac{5}{9}\cdot\dfrac{2}{17}\\ =\dfrac{5}{9}\left(\dfrac{14}{17}+\dfrac{1}{17}+\dfrac{2}{17}\right)\\ =\dfrac{5}{9}\cdot1\\ =\dfrac{5}{9}\)