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\(a,125^5:25^3=\left(5^3\right)^5:\left(5^2\right)^3=5^{15-6}=5^9\)
\(b,27^6:9^3=\left(3^3\right)^6:\left(3^2\right)^3=3^{18-6}=3^{12}\)
\(c,4^{20}:2^{15}=\left(2^2\right)^{20}:2^{15}=2^{40-15}=2^{25}\)
\(d,24^n:2^{2n}=4^n.6^n:4^n=6^n\)
\(e,64^4.16^5:4^{20}=\left(2^6\right)^4.\left(2^4\right)^5:\left(2^2\right)^{20}=2^{24+20-40}=2^4=16\)
d. 513:1254
= 513 : ( 53)4
= 513 : 512
= 51
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a ) A = 82 x 324 = ( 23 )2 x ( 25 )4 = 23.2 x 25.4 = 26 x 220 = 226
b ) B = 273 x 94 x 243 = ( 33 )3 x ( 32 )4 x 35 = 33.3 x 32.4 x 35 = 39 x 38 x 35 = 322
c ) C = 643 : 163 = ( 43 )3 : ( 42 )3 = 43.3 : 42.3 = 49 : 46 = 43
d ) D = 513 : 1254 = 513 : ( 53 )4 = 513 : 53.4 = 513 : 512 = 51
\(A=8^2\cdot32^4\\ =2^6\cdot2^{20}\\ =2^{26}\\ B=27^3\cdot9^4\cdot243\\ =3^9\cdot3^{12}\cdot3^5\\ =3^{26}\)
`A=8^2*32^4=(2^3)^2*(2^5)^4=2^6*2^20=2^26`
`B=27^3*9^4*243=(3^3)^3*(3^2)^4*3^5=3^9*3^8*3^5=3^22`
\(a,\sqrt{2^3}=2^{\dfrac{3}{2}}\\ b,\sqrt[5]{\dfrac{1}{27}}=\sqrt[5]{3^{-3}}=3^{-\dfrac{3}{5}}\\ c,\left(\sqrt[5]{a}\right)^4=\sqrt[5]{a^4}=a^{\dfrac{4}{5}}\)
\(\left(0,25\right)^8=\left[\left(0,5\right)^2\right]^8=\left(0,5\right)^{2.8}=\left(0,5\right)^{16}\)
\(\left(0,125\right)^4=\left[\left(0,5\right)^3\right]^4=\left(0,5\right)^{3.4}=\left(0,5\right)^{12}\)
\(\left(0,0635\right)^2=\left[\left(0,5\right)^3\right]^2=\left(0,5\right)^{3.2}=\left(0,5\right)^6\)
82 x 324 = (23)2 x (25)4 = 26 x 220=226
273 x 94 x243 = 39 x 38x35=322
643 : 163 =218 : 212 = 26
513:1254 = 513 : 512= 5
a: \(4^5\cdot8^7=2^{10}\cdot2^{21}=2^{31}\)
b: \(125^5\cdot25^3=5^{15}\cdot5^6=5^{21}\)
a) 272 : 253
= (33)2 : (52)3
= 36 : 56
\(=\left(\frac{3}{5}\right)^6\)
b) 254 : 28
= (52)4 : 28
= 58 : 28
\(=\left(\frac{5}{2}\right)^8\)
a: \(1=4^0\)
\(4=4^1\)
\(16=4^2\)
\(256=4^4\)
b: \(\dfrac{1}{4}=4^{-1}\)
\(\dfrac{1}{64}=4^{-3}\)
\(\dfrac{1}{256}=4^{-4}\)
\(\dfrac{1}{16}=4^{-2}\)
\(\dfrac{1}{1024}=4^{-5}\)