x2=x5
5y+5y+2=650
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Lời giải:
a.
$=-2x^5+10x^4+2424x^3-x^3-3=-2x^5+10x^4+2423x^3-3$
b.
$=(x-5y)^2+2(x-5y)(x+y)+(x+y)^2$
$=[(x-5y)+(x+y)]^2=(2x-4y)^2=4x^2-16xy+16y^2$
a) 2016x = 2017x
=> 2016x - 2017x =0
=> x(2016 - 2017) =0
=> x(-1)=0
=>x=0:(-1)=0
b) (x-5)2015=(x-5)2014
=> (x-5)2015 - (x-5)2014=0
=> (x-5)(2015-2014)=0
=> x-5=0
=>x=5
c)5x + 5x +2 =650
=> 10x + 2 =650
=> 10x =648
=> x = \(\frac{648}{10}=64,8\)
d) 2017x =2x
=> 2017x -2x =0
=> 2015x=0
=>x=0
a: \(=xy\left(5x-1\right)\)
b: \(=\left(x-2\right)\left(3x-5\right)\)
\(a,=xy\left(5x-1\right)\\ b,=\left(x-2\right)\left(3x-5\right)\\ c,Sửa:x^2+2x+1-9y^2\\ =\left(x+1\right)^2-9y^2\\ =\left(x-3y+1\right)\left(x+3y+1\right)\\ d,=x\left(x-y\right)+5\left(x-y\right)=\left(x+5\right)\left(x-y\right)\)
\(a,=x^2-4-x^2+2x+4=2x\\ b,=\left(x-5y\right)^2:\left(5y-x\right)=\left(5y-x\right)^2:\left(5y-x\right)=5y-x\\ c,Sửa:\left(28x-9x^2+x^3-30\right):\left(x-3\right)\\ =\left(x^3-3x^2-6x^2+18x+10x-30\right):\left(x-3\right)\\ =\left(x-3\right)\left(x^2-6x+10\right)\left(x-3\right)=x^2-6x+10\)
b: (x-y)(x^2-2x+y)
\(=x^3-2x^2+xy-x^2y+2xy-y^2\)
\(=x^3-2x^2-x^2y+3xy-y^2\)
c: \(\left(x^2-y\right)\left(x+y^2\right)-\left(x-y\right)\left(x^2+xy+y^2\right)\)
\(=x^3+x^2y^2-xy-y^3-\left(x^3-y^3\right)\)
\(=x^2y^2-xy\)
d: \(3x\left(2xy-z\right)-5y\left(x^2-2\right)+3xz\)
\(=6x^2y-3xz-5x^2y+10y+3xz\)
\(=x^2y+10y\)
\(x^2=x^5\Rightarrow x\in\left\{0;1\right\}\)
\(5^y+5^{y+2}=650\)
\(\Rightarrow5^y.\left(1+5^2\right)=650\)
\(\Rightarrow5^y.\left(1+25\right)=650\)
\(\Rightarrow5^y.26=650\)
\(\Rightarrow5^y=650:26\)
\(\Rightarrow5^y=25\)
\(\Rightarrow5^y=5^2\)
Vậy y=2.