(x2-( 62-(82-9*7 3)-7*5 ) 3 -5,3) =1
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2 tháng 7 2023
=>{y^2-36+(64-63)^3+7*125-15}^3=1
=>{y^2-51+875+1}=1
=>y^2=-824(vô lý)
26 tháng 7 2021
1) Ta có: \(5\left(x-3\right)\left(x-7\right)-\left(5x+1\right)\left(x-2\right)=-8\)
\(\Leftrightarrow5\left(x^2-10x+21\right)-\left(5x^2-10x+x-2\right)=-8\)
\(\Leftrightarrow5x^2-50x+105-5x^2+9x+2+8=0\)
\(\Leftrightarrow-41x=-115\)
hay \(x=\dfrac{115}{41}\)
2) Ta có: \(x\left(x+1\right)\left(x+2\right)-\left(x+4\right)\left(3x-5\right)=84-5x\)
\(\Leftrightarrow x\left(x^2+3x+2\right)-\left(3x^2+7x-20\right)=84-5x\)
\(\Leftrightarrow x^3+3x^2+2x-3x^2-7x+20-84+5x=0\)
\(\Leftrightarrow x^3=64\)
hay x=4
3) Ta có: \(\left(9x^2-5\right)\left(x+3\right)-3x^2\left(3x+9\right)=\left(x-5\right)\left(x+4\right)-x\left(x-11\right)\)
\(\Leftrightarrow9x^3+27x^2-5x-15-9x^3-27x^2=x^2-x-20-x^2+11x\)
\(\Leftrightarrow-5x-15=10x-20\)
\(\Leftrightarrow-5x-10x=-20+15\)
\(\Leftrightarrow x=\dfrac{-5}{-15}=\dfrac{1}{3}\)
19 tháng 8 2021
Bài 1:
a: Ta có: \(48751-\left(10425+y\right)=3828:12\)
\(\Leftrightarrow y+10425=48751-319=48432\)
hay y=38007
b: Ta có: \(\left(2367-y\right)-\left(2^{10}-7\right)=15^2-20\)
\(\Leftrightarrow2367-y=1222\)
hay y=1145
19 tháng 8 2021
Bài 2:
Ta có: \(8\cdot6+288:\left(x-3\right)^2=50\)
\(\Leftrightarrow288:\left(x-3\right)^2=2\)
\(\Leftrightarrow\left(x-3\right)^2=144\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=12\\x-3=-12\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=15\\x=-9\end{matrix}\right.\)
20 tháng 4 2023
a) 11 : 4 + 5,3 x 3,8
= 3,75 + 5,3 x 3,8
= 3,75 + 20,14
= 23,89
b) 16,52 : 0,5 - 2,7 : 0.25
= 33,04 - 2,7 : 0,25
= 33,04 - 10,8
= 22,24
c) 7/5 : 2/3 : 1,05 - 4/9
= 7/5 : 2/3 : 21/20 - 4/9
= 7/5 x 3/2 x 20/21 - 4/9
= (1 x 3 x 2)/ (1 x 1 x 3)
= 6/3
= 2
TA
10 tháng 10 2020
\(\frac{2}{7}+-\frac{3}{8}+\frac{11}{7}+\frac{1}{7}+\frac{5}{-8}+-5,3\)
\(=\frac{2}{7}+\frac{11}{7}+\frac{1}{7}+\frac{5}{-8}-\frac{3}{8}-5,3\)
\(=2+\frac{5}{-8}-\frac{3}{8}-5,3\)
\(=-3,3-0,625-0,375\)
\(=3,3-1\)
\(=-4,3\)
11 tháng 10 2020
\(\frac{2}{7}+\frac{-3}{8}+\frac{11}{7}+\frac{1}{3}+\frac{1}{7}+\frac{5}{-8}+\left(-5,3\right)\)
\(=\)\(\left(\frac{2}{7}+\frac{11}{7}+\frac{1}{7}\right)+\left(\frac{-3}{8}+\frac{-5}{8}\right)+\left(\frac{1}{3}+\frac{-53}{10}\right)\)
\(=\)\(2+\left(-1\right)+\left(\frac{10}{30}+\frac{-159}{30}\right)\)
\(=\)\(1+\frac{-149}{30}\)\(=\)\(\frac{30}{30}+\frac{-149}{30}\)\(=\)\(\frac{-119}{30}\)
NT
0
LM
Lê Minh Vũ
CTVHS
7 tháng 7 2023
\(4,7\div0,25+5,3\times4\)
\(=18,8+21,2\)
\(=40\)
\(3\times\left(a-2\right)+150=240\)
\(3\times\left(a-2\right)=90\)
\(a-2=30\)
\(a=32\)
\(\dfrac{1}{9}+a+\dfrac{7}{12}=\dfrac{17}{18}\)
\(\dfrac{1}{9}+a=\dfrac{13}{36}\)
\(a=\dfrac{1}{4}\)
\(\left(\dfrac{1}{2}\times\dfrac{1}{3}+\dfrac{1}{3}\times\dfrac{1}{4}+\dfrac{1}{4}\times\dfrac{1}{5}+\dfrac{1}{5}\times\dfrac{1}{6}+\dfrac{1}{6}\times\dfrac{1}{7}+\dfrac{1}{7}\times\dfrac{1}{8}\right)\times a=\dfrac{9}{16}\)
\(\left(\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+\dfrac{1}{4\times5}+\dfrac{1}{5\times6}+\dfrac{1}{6\times7}+\dfrac{1}{7\times8}\right)\times a=\dfrac{9}{16}\)
\(\left(\dfrac{1}{2}-\dfrac{1}{8}\right)\times a=\dfrac{9}{16}\)
\(\dfrac{3}{8}\times a=\dfrac{9}{16}\)
\(a=\dfrac{3}{2}\)
ko hỉu, bn gi rõ hơn đc ko?