Tình tổng M = 1-2+2^2-2^3+.......+2^2016
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Ta có :
\(A=\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+..............+\dfrac{1}{2^{2015}}+\dfrac{1}{2^{2016}}\)
\(2A=1+\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+...........+\dfrac{1}{2^{2015}}\)
\(\Rightarrow2A-A=\left(1+\dfrac{1}{2}+..........+\dfrac{1}{2^{2015}}\right)-\left(\dfrac{1}{2}+\dfrac{1}{2^2}+.......+\dfrac{1}{2^{2016}}\right)\)
\(\Rightarrow A=1-\dfrac{1}{2^{2016}}\)
\(\Rightarrow A=\dfrac{2^{2016}-1}{2^{2016}}\)
~ Học tốt ~
M=2018^2-2017^2+2016^2-2015^2+............+2^2-1^2
M=(2018+2017).(2018-2017)+(2016+2015).(2016-2015)+...........+(2+1).(2-1)
M=2018+2017+2016+2015+.................+2+1
M=2018.(2018+1)/2=2018.2019/2
M=1009.2019M=2037171
\(2.TS=2+2^2+2^3+2^4+...+2^{2017}\)
\(TS=2.TS-TS=2^{2017}-1\)
\(B=\frac{2^{2017}-1}{1-2^{2016}}=-\frac{1-2.2^{2016}}{1-2^{2016}}=-\frac{1-2^{2016}-2^{2016}}{1-2^{2016}}=-\left(1-\frac{2^{2016}}{1-2^{2016}}\right)\)
M = 1-2+22-23+...+22016
2M = 2-22+23-24+...+22017
3M = 2M + M = 1 + 22017
=> M = \(\frac{2^{2017}+1}{3}\)