Tìm x 260 : ( x + 4 ) = 5 ( 2^3 + 5 ) - 3 ( 3^2 + 2^2 )
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a) \(\left(3^2-2\right).\left(x-12+35\right)\)\(=\)\(5^2+279:5\)
\(7.\left(x-12+35\right)=80,8\)
\(x-12+35=80,8:7\)
\(x-12+35=\frac{404}{35}\)
\(x-12=\frac{404}{35}-35\)
\(x-12=\frac{-821}{35}\)
\(x=\frac{-821}{35}+12\)
\(x=\frac{-401}{35}\)
b) \(260:\left(x+4\right)\)\(=\)\(5\left(2^3+5\right)-3\left(3^2+2^2\right)\)
\(260:\left(x+4\right)=26\)
\(x+4=260:26\)
\(x+4=10\)
\(x=10-4\)
\(x=6\)
c) \(7^{x-3}=343\)
\(7^x:7^3=343\)
\(7^x=343.7^3\)
\(7^x=117649\)
vì \(117649=7^6\Rightarrow x=6\)
d) \(\left(x-3\right)^{2017}=\left(x-3\right)^{2016}\)
\(\Rightarrow\hept{\begin{cases}x-3=1\\x-3=0\end{cases}\Rightarrow\hept{\begin{cases}x=4\\x=3\end{cases}}}\)
e) \(\left(2^3+3\right).\left(x-5\right)+14\)\(=\)\(5^2+124:2^2\)
\(\left(2^3+3\right).\left(x-5\right)+14=56\)
\(\left(2^3+3\right).\left(x-5\right)=56-14\)
\(\left(2^3+3\right).\left(x-5\right)=42\)
\(x-5=42:\left(2^3+3\right)\)
\(x-5=\frac{42}{11}\)
\(x=\frac{42}{11}+5\)
\(x=\frac{97}{11}\)
260 : (x+4) = 5 (23 + 5) - 3 (32 + 22)
=> 260 : (x+4) = 5 . 13 - 3 . 13
=> 260 : (x+4) = 13 . (5-3)
=> 260 : (x+4) = 13 . 2
=> 260 : (x + 4) = 26
x + 4 = 260 : 26
x + 4 = 10
=> x = 10 - 4
=> x = 6
sorry tui làm sai câu này!!!
2/3 +4/37 +5/111 +260 /1443
=962/1443+156/1443+65/1443+260/1443
= 962+156+65+260/1443=1
tìm x
1)1/2 - ( x+3/14) = 1/6
=> x+3/14=1/2-1/6
=> x= 1/3 - 3/14
=> x= 5/42
2)( x- 1/3 ) -5/2 = 1/7
=> x-1/3= 1/7+5/2
=> x= 37/14+1/3
=> x= 125/42
3)5/8 + ( x- 1/4 ) = 4/3
=>x-1/4=4/3-5/8
=>x= 17/24 +1/4
=> x= 23/24
4) 4/3 - ( 1/4 -x ) =1
=>1/4-x=4/3-1
=>x=1/4-1/3
=> x= -1/12
Chúc bạn Hk tốt!!!
2/3 +4/37 +5/111 +260 /1443\(=\frac{635}{629}\)
Tìm x
1. \(x=\frac{5}{42}\)
2. \(x=\frac{125}{42}\)
3. \(x=\frac{23}{24}\)
4. \(x=-\frac{1}{12}\)
Chúc bạn Hk tốt!!!
bài 2 :
ta có x:y:z=3:5:(-2)
=>x/3=y/5=z/-2
=>5x/15=y/5=3z/-6
áp dụng tc dãy ... ta có :
5x/15=y/5=3z/-6=5x-y+3z/15-5+(-6)=-16/4=-4
=>x/3=-=>x=-12
=>y/5=-4=>y=-20
=>z/-2=-4=>z=8
Ta có: \(260:\left(x+4\right)=5\left(2^3+5\right)-3\left(3^2+2^2\right)\)
\(\Leftrightarrow260:\left(x+4\right)=26\)
\(\Leftrightarrow x+4=10\)
hay x=6