|x+4/15| - |-3,75| = - |-2,15| tìm x
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| x + 4/15 | - | - 3,75 | = - | - 2,15 |
| x + 4/15 | - 3,75 = - 2,15
| x + 4/15 | = - 2,15 + 3,75
| x + 4/15 | = 1,6
Trường hợp 1 : x + 4/15 = 1,6 suy ra x = 4/3
Trương hợp 2: x + 4/15 = - 1,6 suy ra x = -28/15
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\Rightarrow\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=-2,15+3,75\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=1,6\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=\frac{8}{5}\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=-\frac{8}{5}\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{4}{3}\\x=-\frac{28}{15}\end{array}\right.\)
Ta có : \(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\Leftrightarrow\left|x+\frac{4}{15}\right|=3,75-2,15=\frac{8}{5}\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{4}{15}=\frac{8}{5}\\-x-\frac{4}{15}=\frac{8}{5}\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=\frac{4}{3}\\x=-\frac{28}{15}\end{array}\right.\)
\(\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\Leftrightarrow\left|x+\dfrac{4}{15}\right|=-2,15+3,75\)
\(\Leftrightarrow\left|x+\dfrac{4}{15}\right|=\dfrac{8}{5}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{4}{15}=\dfrac{8}{5}\\x+\dfrac{4}{15}=-\dfrac{8}{5}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=-\dfrac{28}{15}\end{matrix}\right.\)
\(\Rightarrow\left|x+\dfrac{4}{15}\right|-3,75=-2,15\\ \Rightarrow\left|x+\dfrac{4}{15}\right|=1,6=\dfrac{8}{5}\\ \Rightarrow\left[{}\begin{matrix}x+\dfrac{4}{15}=\dfrac{8}{5}\\x+\dfrac{4}{15}=-\dfrac{8}{5}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=-\dfrac{28}{15}\end{matrix}\right.\)
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\left|x+\frac{4}{15}\right|=-2,15+3,75\)
\(\left|x+\frac{4}{15}\right|=1,6\)
+) \(x+\frac{4}{15}=16\)
\(\Rightarrow x=\frac{236}{15}\)
+) \(x+\frac{4}{15}=-16\)
\(\Rightarrow x=-\frac{244}{15}\)
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\Rightarrow\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=-2,15+3,75\)
\(\Rightarrow\left|x+\frac{4}{15}\right|=1,6=\frac{8}{5}\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{4}{15}=\frac{8}{5}\\x+\frac{4}{15}=\frac{-8}{5}\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{4}{3}\\x=\frac{-28}{15}\end{array}\right.\)
Vậy \(\left[\begin{array}{nghiempt}x=\frac{4}{3}\\x=\frac{-28}{15}\end{array}\right.\)
/x+4/15/-/-3,75/=-/-2,15/
/x+4/15/-15/4=-\(\frac{43}{20}\)
x+4/15=\(\frac{43}{20}+\frac{15}{4}\)
x+4/15=59/10
x=59/10-4/15
x=\(5\frac{19}{30}\)
/x + \(\frac{4}{15}\)/ - 3,75 = -2,15
=> /x + \(\frac{4}{15}\)/ = 1,6
=> \(x+\frac{4}{5}=1,6\) hoặc \(x+\frac{4}{5}=-1,6\)
=> \(x=0,8\)hoặc \(x=-2,4\)
\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\left|x+\frac{4}{15}\right|-3,75=-2,15\)
\(\left|x+\frac{4}{15}\right|=-2,15+3,75\)
\(\left|x+\frac{4}{15}\right|=1,6\)
Ta có 2 trường hợp
trường hợp 1
\(x+\frac{4}{15}=1,6\)
\(x=1,6-\frac{4}{15}\)
\(x=\frac{4}{3}\)
Trường hợp 2
\(x+\frac{4}{15}=-1,6\)
\(x=-1,6-\frac{4}{15}\)
\(x=\frac{-28}{15}\)
Vậy \(x=\left\{-\frac{28}{15};\frac{4}{3}\right\}\)
|x+4/15|-|-3,75|=-|-2,15|
|x+4/15|-3,75=-2,15
|x+4/15|=-2,15+3,75
|x+4/15|= 1,6 hoặc -1,6
Với x+4/15= 1,6 => x = 1,6-4/15 = 4/3
Với x+4/15= -1,6 => x = -1,6-4/15= -28/15
Vậy x= 4/3 hoặc x = -28/15