3.25+15.4-26:2
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a, ta có \(\frac{2.\left(-13\right).9.10}{\left(-3\right).4.\left(-5\right).26}\)=\(\frac{2.\left(-13\right).\left(-3\right).\left(-3\right).2.\left(-5\right)}{\left(-3\right).2.2.\left(-5\right).\left(-2\right).\left(-13\right)}\)
rút gọn đi còn: \(\frac{-3}{-2}\)=\(\frac{3}{2}\)
a) Ta có: \(\frac{2\cdot\left(-13\right)\cdot9\cdot10}{\left(-3\right)\cdot4\cdot\left(-5\right)\cdot26}=\)\(\frac{2\cdot\left(-1\right)\cdot13\cdot3\cdot3\cdot2\cdot5}{3\cdot\left(-1\right)2\cdot2\cdot\left(-1\right)\cdot5\cdot2\cdot13}\)=\(-3.\)
b)Ta có: \(\frac{15\cdot8+15\cdot4}{12\cdot3}=\frac{15\left(8+4\right)}{12\cdot3}\)=\(\frac{15\cdot12}{12\cdot3}=\frac{15}{3}=5\)
a) \(\frac{2.\left(-13\right).9.10}{\left(-3\right).4.\left(-5\right).26}=\frac{18.\left(-130\right)}{\left(-12\right).\left(-130\right)}=\frac{-3}{2}\)
b) \(\frac{15.8+15.4}{12.3}=\frac{15.\left(8+4\right)}{12.3}=\frac{15.12}{12.3}=5\)
a) Ta có: \(\frac{2.\left(-13\right).9.10}{\left(-3\right).4.\left(-5\right).26}=\frac{2.\left(-13\right).3^2.2.5}{3.2^2.5.2.13}\)
\(=\frac{\left(-13\right).2^2.3^2.5}{2^3.3.5.13}\)
\(=-\frac{3}{2}\)
b) Ta có: \(\frac{15.8+15.4}{12.3}=\frac{3.5.\left(8+4\right)}{2^2.3.3}\)
\(=\frac{3.5.2^2.3}{2^2.3.3}\)
\(=5\)
a: \(=\dfrac{2^{19}\cdot3^9+2^{20}\cdot3^{10}}{2^{19}\cdot3^9+2^{18}\cdot3^9\cdot5}=\dfrac{2^{19}\cdot3^9\left(1+2\cdot3\right)}{2^{18}\cdot3^9\left(2+5\right)}=2\)
\(=3,25\times4+6\times3,25\)
\(=3,25\times\left(4+6\right)\)
\(=3,25\times10\)
\(=32,5\)
76 - { 2 . [ 2 . 52 - ( 31 - 2.3 ) ] } + 3. 25
= 76 - { 2 .[ 50 - ( 31 - 6 ) ] } + 75
= 76 - {2 . [ 50 - 25 ] } + 75
= 76 - { 2 . 25 } + 75
= 76 - 100 + 75
= 51.
3.25+15.4-26:2
= 75 + 60 - 13
= 135 - 13
= 122
3.25 + 15.4 - 26:2
= 75 + 60 + 13
= 135 + 13 =148