Tìm x,y:
a,/x-y+2/+/2y+1/<hoặc=0.
b,/x-1/+/2-x/=4.
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a) | x - 1, 3 | + | 5, 3 - y | = 0
Ta có : \(\hept{\begin{cases}\left|x-1,3\right|\ge0\forall x\\\left|5,3-y\right|\ge0\forall y\end{cases}}\Rightarrow\left|x-1,3\right|+\left|5,3-y\right|\ge0\forall x,y\)
Dấu "=" xảy ra <=> \(\hept{\begin{cases}x-1,3=0\\5,3-y=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x=1,3\\y=5,3\end{cases}}\)
Vậy x = 1, 3 ; y = 5, 3
b) | x + 2 | + | 4/5 - 2y | = 0
Ta có : \(\hept{\begin{cases}\left|x+2\right|\ge0\forall x\\\left|\frac{4}{5}-2y\right|\ge0\forall y\end{cases}}\Rightarrow\left|x+2\right|+\left|\frac{4}{5}-2y\right|\ge0\forall x,y\)
Dấu "=" xảy ra <=> \(\hept{\begin{cases}x+2=0\\\frac{4}{5}-2y=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x=-2\\y=\frac{2}{5}\end{cases}}\)
Vậy x = -2 ; y = 2/5
Tìm y:
\(a,y+847\times2=1953-74\\ y+847\times2=1879\\ y+1694=1897\\ y=1897-1694\\ y=185\\ b,y:\left(7\times18\right)=5839+8591\\ y:126=14430\\ y=14430\times126\\ y=1818180.\)
a: Ta có: \(x^2\ge0\forall x\)
\(\left(y-\dfrac{1}{10}\right)^4\ge0\forall y\)
Do đó: \(x^2+\left(y-\dfrac{1}{10}\right)^4\ge0\forall x,y\)
Dấu '=' xảy ra khi \(\left(x,y\right)=\left(0;\dfrac{1}{10}\right)\)
\(a,y\times2,8+5,2\times y=48\\ y\times\left(2,8+5,2\right)=48\\ y\times8=48\\ y=\dfrac{48}{8}=6\\ ---\\ b,y\times12,25-y+y\times2,75=1050\\ y\times\left(12,25-1+2,75\right)=1050\\ y\times14=1050\\ y=\dfrac{1050}{14}=75\)
a: \(y\cdot2,8+y\cdot5,2=48\)
=>\(y\left(2,8+5,2\right)=48\)
=>\(8y=48\)
=>\(y=\dfrac{48}{8}=6\)
b: \(y\cdot12,25-y+y\cdot2,75=1050\)
=>\(y\left(12,25-1+2,75\right)=1050\)
=>\(y\cdot14=1050\)
=>\(y=\dfrac{1050}{14}=75\)
\(a,y\times27+y\times30+y\times44-y=10500\\\Rightarrow y\times\left(27+30+44-1\right)=10500\\ \Rightarrow y\times100=10500\\ \Rightarrow y=10500:100\\ \Rightarrow y=105\\ b,y\times285+115\times y=400\\ \Rightarrow y\times\left(285+115\right)=40\\ \Rightarrow y\times400=400\\ y=400:400\\ \Rightarrow y=1\)
\(a,\Rightarrow y\times\left(27+30+44-1\right)=10500\\ \Rightarrow y\times100=10500\\ \Rightarrow y=105\\ b,\Rightarrow y\times\left(285+115\right)=400\\ \Rightarrow y\times400=400\\ \Rightarrow y=1\)
Có: \(\left\{{}\begin{matrix}\left|x-3\right|\ge0\forall x\\\left|y-1\right|\ge0\forall y\end{matrix}\right.\)
\(\Rightarrow\left|x-3\right|+\left|y-1\right|\ge0\forall x;y\)
Mà: \(\left|x-3\right|+\left|y-1\right|=0\)
nên: \(\left\{{}\begin{matrix}x-3=0\\y-1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=3\\y=1\end{matrix}\right.\)
a) (y + 5) x 2020 = 205 x 2020
(y + 5) x 2020 = 414100
y + 5 = 414100 : 2020 = 205
y = 205 - 5 = 200
a) y= 200
b) y-45600 = 1600 × 4 ×25
y-45600=160000
y= 114400
a)Ta thấy:\(\begin{cases}\left|x-y+2\right|\ge0\\\left|2y+1\right|\ge0\end{cases}\)
\(\Rightarrow\left|x-y+2\right|+\left|2y+1\right|\ge0\) (1)
Mà \(\left|x-y+2\right|+\left|2y+1\right|\le0\) (2)
Từ (1) và (2) suy ra:
\(\left|x-y+2\right|+\left|2y+1\right|=0\)\(\Rightarrow\begin{cases}\left|x-y+2\right|=0\\\left|2y+1\right|=0\end{cases}\)
\(\Rightarrow\begin{cases}x-y+2=0\\2y+1=0\end{cases}\)\(\Rightarrow\begin{cases}x-y+2=0\\y=-\frac{1}{2}\end{cases}\)
\(\Rightarrow\begin{cases}x-\left(-\frac{1}{2}\right)+2=0\\y=-\frac{1}{2}\end{cases}\)\(\Rightarrow\begin{cases}x=-\frac{5}{2}\\y=-\frac{1}{2}\end{cases}\)
b) Ta có: \(\left|x-1\right|\ge0\)
\(\left|2-x\right|\ge0\)
\(\Rightarrow\left|x-1\right|+\left|2-x\right|=4>0\)
\(\Rightarrow\left|x-1\right|+\left|2-x\right|=x-1+2-x=4\)
\(\Rightarrow\left(x-x\right)-\left(1-2\right)=4\)
\(\Rightarrow0+1=4\) ( vô lí )
Vậy x không có giá trị thỏa mãn