so sánh A và 10.98 mà: A=1+2+22+23+...+29
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


a) Ta có \(\dfrac{23}{27}>\dfrac{23}{29};\dfrac{23}{29}>\dfrac{22}{29}\)
Vậy \(\dfrac{23}{27}>\dfrac{22}{29}\)
b) Ta có \(\dfrac{15}{25}=1-\dfrac{2}{5}\)
\(\dfrac{25}{49}=1-\dfrac{24}{49}\)
Vì \(\dfrac{2}{5}=\dfrac{24}{60}< \dfrac{24}{49}\)
Vậy \(\dfrac{15}{25}>\dfrac{25}{49}\)

Ta lấy ps trung gian: 23/29
So sánh : 23/27>23/29>22/29.
=> 23/27>22/29

S=1+2+22+...+29�=1+2+22+...+29
2S=2(1+2+22+...+210)2�=2(1+2+22+...+210)
2S=2+22+23+...+292�=2+22+23+...+29
2S−S=(2+22+23+...+210)−(1+2+22+...+29)2�−�=(2+22+23+...+210)−(1+2+22+...+29)
\(S=2^{10}-1=2^2.2^8-1=4.2^8-1
HT
S=1+2+22+...+29�=1+2+22+...+29
2S=2(1+2+22+...+210)2�=2(1+2+22+...+210)
2S=2+22+23+...+292�=2+22+23+...+29
2S−S=(2+22+23+...+210)−(1+2+22+...+29)2�−�=(2+22+23+...+210)−(1+2+22+...+29)
\(S=2^{10}-1=2^2.2^8-1=4.2^8-1

\(S=1+2+2^2+2^3+...+2^9\)
Đặt \(2S=2+2^2+2^3+2^4+...+2^{10}\)
\(2S-S=2^{10}-1\) hay \(S=2^{10}-1< 2^{10}\)
\(\Rightarrow\) \(2^{10}=2^2.2^8< 5.2^8\)
Vậy \(S< 5.2^8\)
\(#Tuyết\)
2S=2+2^2+...+2^10
=>S=2^10-1=1023
5*2^8=256*5=1280
=>S<5*2^8

Ta có A = \(\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}+\dfrac{1}{110}+\dfrac{1}{132}\)
= \(\dfrac{1}{6\cdot7}+\dfrac{1}{7\cdot8}+\dfrac{1}{8\cdot9}+\dfrac{1}{9\cdot10}+\dfrac{1}{10\cdot11}+\dfrac{1}{11\cdot12}\)
= \(\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{12}\)
= \(\dfrac{1}{6}-\dfrac{1}{12}=\dfrac{1}{12}\)
B = \(\dfrac{\dfrac{2}{29}-\dfrac{2}{39}+\dfrac{2}{49}}{\dfrac{23}{29}-\dfrac{23}{39}+\dfrac{23}{49}}=\dfrac{2\left(\dfrac{1}{29}-\dfrac{1}{39}+\dfrac{1}{49}\right)}{23\left(\dfrac{1}{29}-\dfrac{1}{39}+\dfrac{1}{49}\right)}=\dfrac{2}{23}\)
Lại có \(\dfrac{2}{23}>\dfrac{2}{24}=\dfrac{1}{12}\) hay A < B
Vậy A < B

a) Có : 23/27>22/27
Mà 22/27>22/29
=> 23/27>22/29
b) Có : 12/25=24/50
24/50<24/49;24/49<25/49
=> 12/25<25/49
a,23/27>23/29
22/29<23/29
=>22/29<23/29<23/27
=>22/29<23/27
kl:....(kết luận)

a) Ta thấy 23/27>23/29 và 23/29>22/29 nên =>23/27>22/29
b) Ta thấy 25/74>1/3 và 1/3>12/37 nên 25/74>12/37
chúc bạn học tốt nha, nếu bạn muốn thì kết bạn với mình mình cho công thức luôn
B)25/74 và 12/37
Ta có 12/37=12*2/37*2
=24/74
=>25/74>24/74
Hay 25/74>12/37


A=210-1<210+28=22.28+1.28=(22+1).28=10.98
=> A<B