a) |x + 2| - 6x = 1
b) |x - 3| + |x - 2| = 7
c) |2x + 1| + |x + 8| = 4x
d) 4x + 4x+3 = 4160
e) (x - 2,5) : \(1\frac{1}{2}\) = x : 2
g) \(\left(\frac{1}{3}+x\right):\left(x+\frac{3}{4}\right)=\frac{7}{9}\)
h) 0,81 : \(\frac{x}{2}=\frac{16}{x^4}:\left(-0,9\right)\)
giúp mk nhé
a: \(\Leftrightarrow\left|x+2\right|=6x+1\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>=-\dfrac{1}{6}\\\left(6x+1-x-2\right)\left(6x+1+x+2\right)=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\ge-\dfrac{1}{6}\\\left(5x-1\right)\left(7x+3\right)=0\end{matrix}\right.\)
\(\Leftrightarrow x=\dfrac{1}{5}\)
b: Trường hợp 1: x<2
Pt sẽ là 3-x+2-x=7
=>5-2x=7
=>2x=-2
hay x=-1(nhận)
Trường hợp 2: 2<=x<3
Pt sẽ là 3-x+x-2=7
=>1=7(vô lý)
Trường hợp 3: x>=3
Pt sẽ là x-3+x-2=7
=>2x-5=7
=>x=6(nhận)
d: \(\Leftrightarrow4^x\cdot\left(1+4^3\right)=4160\)
\(\Leftrightarrow4^x=64\)
hay x=3