100-[116-(13-52)]
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{30}{13}\)× \(\frac{52}{29}\)×\(\frac{116}{240}\)= \(\frac{3×10×13×4×29×4}{13×29×2×3×4×10}\)( gạch số giống nhau đi )=\(\frac{4}{2}\)= 2
![](https://rs.olm.vn/images/avt/0.png?1311)
a) A= 100 - 116 : 4
=100-29
=71
b) B= 100 - [ 116 - (13 - 5)2]
=100-[116-82]
=100-(116-64)
=100-52
=48
c) C= |- 65| + (- 42) + |65|
= 65+(-42)+65
= 88
![](https://rs.olm.vn/images/avt/0.png?1311)
\(13\cdot16+13\cdot\left(-116\right)+17\cdot\left(-100\right)\)
\(=13\left(16+-116\right)+17\cdot\left(-100\right)\)
\(=13\cdot\left(-100\right)+17\cdot\left(-100\right)\)
\(=\left(-100\right)\cdot\left(13+17\right)=30\cdot\left(-100\right)=-3000\)
13.16+13.(-116)+17.(-100)
=13.(-116+16)+17.(-100)
=13.(-100)+17.(-100)
=(-100).(13+17)
=-100.30
=(-3000)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(100-\left[116-\left(13-5\right)^2\right]\)
\(=100-\left(116-8^2\right)\)
\(=100-\left(116-64\right)\)
\(=100-52\)
\(=48\)
![](https://rs.olm.vn/images/avt/0.png?1311)
b) /2x-5/=13
=>2x-5=13 hoặc -13
TH1: 2x-5=13 | TH2:2x-5=-13 |
2x=13+5=>2x=18 | 2x=-13+5=>2x=-8 |
x=18:2=>x=9 | x=-8:2=>x=4 |
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(30\left(x+2\right)-6\left(x-5\right)-24x=100\)
\(\Leftrightarrow30x+60-6x+30-24x=100\)
\(\Leftrightarrow\left(30x-6x-24x\right)+\left(60+30\right)\)
\(\Leftrightarrow x\left(30-6-24\right)+90=100\)
\(\Leftrightarrow0x+90=100\)
\(\Leftrightarrow0x=100-90\)
\(\Leftrightarrow0x=10\)
\(\Rightarrow\)Không có x thoả mãn.
b) \(|2x-5|=13\)
\(\Rightarrow\orbr{\begin{cases}2x-5=13\\2x-5=-13\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x=18\\2x=-8\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=9\\x=-4\end{cases}}\)
Vậy \(x\in\left\{-4;9\right\}\)
c) \(52-|x|=80\)
\(\Leftrightarrow|x|=52-80\)
\(\Leftrightarrow|x|=-28\)
Vì \(|x|\ge0\)
\(\Rightarrow\)Không có x thoả mãn.
\(100-\left(116-\left(13-5^2\right)\right)=100-\left(116-\left(-12\right)\right)\)
\(=100-\left(116+12\right)=100-128=-28\)
100-[116-(13-52)]
=100-[116-(13-25)]
=100-(116-13+25)
=100-(103+25)
=100-128
=-28