25.9+25.1.20=
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\(\left(4x-1\right)^2=25.9=225\\ \Leftrightarrow\left(4x-1\right)^2=15^2=\left(-15\right)^2\\ \Leftrightarrow\left[{}\begin{matrix}4x-1=15\\4x-1=-15\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}4x=16\\4x=-14\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{16}{4}=4\\x=-\dfrac{14}{4}=-\dfrac{7}{2}\end{matrix}\right.\)
\(\left(4x-1\right)^2=25\cdot9\)
\(\Rightarrow\left(4x-1\right)^2=5^2\cdot3^2\)
\(\Rightarrow\left(4x-1\right)^2=\left(5\cdot3\right)^2\)
\(\Rightarrow\left(4x-1\right)^2=15^2\)
TH1: \(4x-1=15\)
\(\Rightarrow4x=15+1\)
\(\Rightarrow4x=16\)
\(\Rightarrow x=\dfrac{16}{4}\)
\(\Rightarrow x=4\)
TH2: \(4x-1=-15\)
\(\Rightarrow4x=-15+1\)
\(\Rightarrow4x=-14\)
\(\Rightarrow x=-\dfrac{14}{4}\)
\(\Rightarrow x=-\dfrac{7}{2}\)
\(\left(4x-1\right)^2=25.9\\ \Leftrightarrow\left(4x-1\right)^2=225\\ \Leftrightarrow\left[{}\begin{matrix}\left(4x-1\right)^2=15^2\\\left(4x-1\right)^2=\left(-15\right)^2\end{matrix}\right.\\\Leftrightarrow\left[{}\begin{matrix}4x-1=15\\4x-1=-15\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}4x=16\\4x=-14\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-\dfrac{7}{2}\end{matrix}\right.\)
(4x-1)^2=(5/3)^2
Suy ra: 4x-1=5/3
4x=5/3+1
4x=8/3
X=8/3:4
X=....
\(\frac{25\cdot9-25\cdot17}{-8\cdot80-8\cdot10}=\frac{25\cdot(9-17)}{8\cdot(-80)-8\cdot10}=\frac{25\cdot(-8)}{8\cdot(-80-10)}=\frac{25\cdot(-8)}{8\cdot(-90)}=\frac{5}{18}\)
P/S : Hoq chắc :>
\(\frac{25.9-25.17}{-8.80-8.10}\)= \(\frac{25\left(9-17\right)}{-8\left(80+10\right)}\)= \(\frac{25.\left(-8\right)}{90.\left(-8\right)}\)= \(\frac{25}{90}\)= \(\frac{5}{18}\)
846 : [41 - (7x - 5)] = 47
41 - (7x - 5)=846:47=18
7x - 5=41-18=23
7x=23+5=28
x=28:7=4
(4x-1)2 = 225
(4x-1)2 = 152 = (-15)2
<=> 4x-1 = 15 hoặc 4x-1 = -15
4x = 16 hoặc 4x = -14
x = 4 hoặc x = - 3,5
Các bạn hãy giúp mình giải bài toán này nhé
Tìm x thuộc N biết
2^x+2^x^3=144
ai đó gúip
. là nhân à bn