Tính nhanh \(\frac{65+891+135+909}{731-47+69-253}=\)
\(\frac{1994.1993-1992.1993}{1992.1993+1994.7+1986}\) =
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1)
\(\frac{1994.1993-1992.1993}{1992.1993+1944.7+1986}\)
\(=\frac{\left(1994-1992\right).1993}{2.1985028+2.6804+2.993}\)
\(=\frac{2.1993}{2.\left(1985028+6804+993\right)}\)
\(=\frac{2.1993}{2.1992825}\)
\(=\frac{193}{1992825}\)
2)
a) \(\frac{399.45+55.399}{1995.1996-1991.1995}\)
\(=\frac{399.\left(45+55\right)}{1995.\left(1996-1991\right)}\)
\(=\frac{399.100}{1995.5}\)\(=4\)
Câu b bài 2 mình không biết làm nữa, xin lỗi nhé!
\(A=\frac{65+891+135+909}{731-47+69-253}\)
\(A=\frac{65+135+891+909}{731+69-47-253}\)
\(A=\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47+253\right)}\)
\(A=\frac{200+1800}{800-300}\)
\(A=\frac{2000}{500}=4\)
A = \(\frac{65+891+135+909}{731-47+69-253}\)
A = \(\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47+253\right)}\)
A = \(\frac{200+1800}{800-300}\)
A = \(\frac{2000}{500}\)
A = 4
\(A=\frac{595959}{454545}-\frac{14141414}{15151515}\)
\(A=\frac{595959:10101}{454545:10101}-\frac{14141414:1010101}{15151515:1010101}\)
\(A=\frac{59}{45}-\frac{14}{15}\)
\(A=\frac{59}{45}-\frac{42}{45}=\frac{17}{45}\)
\(B=\frac{65+891+135+909}{731-47+69-253}\)
\(B=\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47+253\right)}\)
\(B=\frac{200+1800}{800-300}=\frac{2000}{500}=4\)
\(C=\frac{65+891+135+909}{731-47+69-253}\)
\(C=\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47+253\right)}\)
\(C=\frac{200+1800}{800-300}\)
\(C=\frac{2000}{500}=4\)