tim x dua vao quan he uoc boi:tim so tu nhien x sao cho x-1 la uoc cua 12tim so tu nhien x sao cho 2x+1 la uoc cua 28tim so tu nhien x sao cho x+15 la boi cua x+3tim cac so nguyen x,y sao cho (x+1)(y-2)=3tim so nguyen x sao cho(x+2).(y-1)=2tim so nguyen to x vua la uoc cua 275 vua la uoc cua 180tim so nguyen to x,y biet x+y=12 va UCLL (x:y)=5tim so tu nhien x,y biet x+y=32 va UCLL (x:y)=8tim so tu nhien x biet x chia het cho10; xchia het cho12; x chia het cho15 va 100<x<150tim so x nho nhat khac 0b...
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tim x dua vao quan he uoc boi:
tim so tu nhien x sao cho x-1 la uoc cua 12
tim so tu nhien x sao cho 2x+1 la uoc cua 28
tim so tu nhien x sao cho x+15 la boi cua x+3
tim cac so nguyen x,y sao cho (x+1)(y-2)=3
tim so nguyen x sao cho(x+2).(y-1)=2
tim so nguyen to x vua la uoc cua 275 vua la uoc cua 180
tim so nguyen to x,y biet x+y=12 va UCLL (x:y)=5
tim so tu nhien x,y biet x+y=32 va UCLL (x:y)=8
tim so tu nhien x biet x chia het cho10; xchia het cho12; x chia het cho15 va 100<x<150
tim so x nho nhat khac 0b biet x chia het cho 24 va 30
40 chia het cho x . 56 chia het cho x va x>6
Ta có: \(\dfrac{x-1}{6}=\dfrac{-2y+3}{30}\)
\(\Leftrightarrow\dfrac{3x-3}{18}=\dfrac{-8y+12}{120}\)
Áp dụng tính chất của dãy tỉ số bằng nhau, ta được:
\(\dfrac{3x-3}{18}=\dfrac{-8y+12}{120}=\dfrac{3x-3+8y-12}{18-120}=\dfrac{2-15}{-102}=\dfrac{13}{102}\)
Do đó:
\(\left\{{}\begin{matrix}\dfrac{x-1}{6}=\dfrac{13}{102}\\\dfrac{3-2y}{30}=\dfrac{13}{102}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x-1=\dfrac{13}{17}\\-2y+3=\dfrac{65}{17}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{30}{17}\\-2y=\dfrac{14}{17}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{30}{17}\\y=\dfrac{-7}{17}\end{matrix}\right.\)
Ta có: 5x - 5 = 3 - 2y
=> 5x+2y = 8
=> 20x + 8y = 32
Mà 3x +8y = 2
=> 17x = 30
=> x = \(\dfrac{30}{7}\)
=> y = ... giải tiếp nha bạn.
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