Question

[Hanako-chan]

Cứu≥﹏≤

Answer 1

[Trần Ái Linh]

`(1/2 x-3)^2=(1/2x-3)^4`

`(1/2x-3)^2-(1/2x-3)^4=0`

`(1/2x-3)^2 [1-(1/2x-3)^2]=0`

`[(1/2x-3=0),((1/2x-3)^2=1^2=(-1)^2):}`

`[(x=6),(1/2x-3=1),(1/2x-3=-1):}`

`[(x=6),(x=8),(x=4):}`

Answer 2

[Hanako-chan]

Cảm ơn bạn >3<