Tìm x:
a. 35x2 - 49= 10x22
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a: Ta có: \(71-\left(x+33\right)=26\)
\(\Leftrightarrow x+33=45\)
hay x=12
b: Ta có: \(\left(x+73\right)-26=76\)
\(\Leftrightarrow x+73=102\)
hay x=29
c: Ta có: \(45-\left(x+9\right)=6\)
\(\Leftrightarrow x+9=39\)
hay x=30
a) 71 - ( 33 + x ) = 26
(33 + x ) = 71 -26
33 + x = 45
x = 45 - 33 = 12
b) ( x + 73 ) - 26 = 76
( x + 73 ) = 102
x = 102 - 73 = 29
c) 45 - ( x + 9 ) = 6
( x + 9 ) = 45 - 6 = 39
x = 39 - 9 = 30
d) 89 - ( 73 - x ) = 20
73 - x = 89 - 20
73 - x = 69
x = 73 - 69 = 4
e) 4(x+41) = 400
x + 41 = 400 : 4 = 100
x = 100 - 41 = 59
f) 11(x-9 ) = 77
x - 9 = 77 : 11 = 7
x = 7 + 9 = 16
g) x + 7 = 25 + 13 = 38
x = 38 - 7 = 31
h) x + 4 = 198 - 120 = 78
x = 78 - 4 = 74
i) x - 9 = 350 : 5 = 70
x = 70 + 9 = 79
j) 2x - 49 = 5 . 9 = 45
2x = 45 + 49 = 94
x = 94 : 2 = 47
k) 25 + 3( x - 8 ) = 106
3(x-8 ) = 106 - 25 = 81
x - 8 = 81 : 3 = 27
x = 27 +8= 35
l) 9( x + 4 ) - 25 = 20
9( x + 4 ) = 20 + 25 = 45
x + 4 =45 : 9 = 5
x = 5 - 4 = 1
m) 200 - ( 2x + 6 ) = 64
2x + 6 = 200 - 64 = 136
2x = 136 - 6 = 130
x = 130 : 2 = 65
a)\(1,5-2\left|x\right|=-0,5\)
\(\Leftrightarrow2\left|x\right|=1,5+0,5\)
\(\Leftrightarrow\left|x\right|=1\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-1\end{matrix}\right.\)
\(\left[2040:\left(47-3x\right)+33\right].11=1683\)
\(\Leftrightarrow2040:\left(47-3x\right)+33=153\)
\(\Leftrightarrow2040\left(47-3x\right)=120\)
\(\Leftrightarrow47-3x=17\)
\(\Leftrightarrow3x=30\Leftrightarrow x=10\)
\(35x^2-49=10x^2< =>25x^2-7^2=0\)
\(< =>\left(5x\right)^2-7^2=0< =>\left(5x+7\right)\left(5x-7\right)=0\)
\(=>\left[{}\begin{matrix}x=-\dfrac{7}{5}\\x=\dfrac{7}{5}\end{matrix}\right.\)
Ta có: \(35x^2-49=10x^2\)
\(\Leftrightarrow25x^2-49=0\)
\(\Leftrightarrow\left(5x-7\right)\left(5x+7\right)=0\)
\(\Leftrightarrow x\in\left\{\dfrac{7}{5};-\dfrac{7}{5}\right\}\)