Thu gọn biểu thức sau:
a)\(\left(-7\right)^5\cdot\left(-7\right)^6\) b) \(\left(-0,7\right)^{10}:\left(-0,7\right)^6\)
c) \(\left(\frac{9}{5}\right)^3\cdot\left(\frac{9}{5}\right)^{10}\) d) \(\left(\frac{-1}{3}\right)^{30}\cdot\left(\frac{1}{3}\right)^{15}\)
a) ( -7 )5 . ( -7 )6 = ( -7 )11
b) ( -0,7 )10 : ( -0,7 )6 = ( -0,7 )4
\(\text{c)}\left(\frac{9}{5}\right)^3.\left(\frac{9}{5}\right)^{10}=\left(\frac{9}{5}\right)^{13}\)
\(\text{d) }\left(\frac{-1}{3}\right)^{30}.\left(\frac{1}{3}\right)^{15}=\left(\frac{1}{3}\right)^{30}.\left(\frac{1}{3}\right)^{15}=\left(\frac{1}{3}\right)^{45}\)
a) \(\left(-7\right)^5.\left(-7\right)^6\)\(=\left(-7\right)^{11}\)
b)\(\left(-0,7\right)^{10}:\left(-0,7\right)^6\)\(=\left(-0,7\right)^4\)
c) \(\left(\frac{9}{5}\right)^3.\left(\frac{9}{5}\right)^{10}=\left(\frac{9}{5}\right)^{13}\)
d) \(\left(-\frac{1}{3}\right)^{30}.\left(\frac{1}{3}\right)^{15}=\left(-\frac{1}{3}\right)^{45}\)