2 x (X-8)=50
2 x X -8=50
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Ta có: \(502\times m+n\)
Tại \(\hept{\begin{cases}m=4\\n=8\end{cases}}\) ta được:
\(BT=502\times4+8=2016\)
4 × 125 × 25 × 8
= (4 × 25) × (125 × 8)
= 100 × 1000
= 100 000
2 × 8 × 50 × 25 × 125
= (2 × 50) × (8 × 125) × 25
= 100 × 1000 × 125
= 12 500 000
2 × 3 × 4 × 5 × 50 × 25
= (2 × 50) × (4 × 25) × (3 × 5)
= 100 × 100 × 15
= 150 000
25 × 20 × 125 × 8 - 8 × 20 × 5 × 125
= 8 × 125 × 20 × (25 - 5)
= 1000 × 20 × 20
= 400 000
- (25 x 4) x (125 x8)=100 x 1000 =100000
- (50 x 2) x (8 x 125) x 25=100 x 1000 x 25 =2500000
- (2 x 50 ) x (4 x 25) x (3 x5)=100 x 100 x 15=150000
- 25 x 20 x125 x 8 - 5
= (20 x 5) x (125 x 8) -25=100 x 1000 -5 =100000 - 5 =99995
n) Theo bài ra ta có: \(\frac{x+1}{2008}=\frac{502}{x+1}\)
=> (x+1).(x+1) = 2008.502
=> (x+1)2 = 1008016
=> (x+1)2 = 10042
=> x+1 = 1004
=> x = 2004-1
=> x = 2003
Vậy x = 2003
p) Theo bà ra ta có: \(\left|\frac{5}{4}.x-\frac{7}{2}\right|-\left|\frac{5}{8}.x+\frac{3}{5}\right|=0\)
=> \(\left|\frac{5}{4}.x-\frac{7}{2}\right|=\left|\frac{5}{8}.x+\frac{3}{5}\right|\)
=> \(\frac{5}{4}.x-\frac{7}{2}=\pm\left(\frac{5}{8}.x+\frac{3}{5}\right)\)
=> \(\left[\begin{array}{nghiempt}\frac{5}{4}.x-\frac{7}{2}=\frac{5}{8}.x+\frac{3}{5}\\\frac{5}{4}.x-\frac{7}{2}=\frac{-5}{8}.x-\frac{3}{5}\end{array}\right.\)
=> \(\left[\begin{array}{nghiempt}\frac{5}{4}.x-\frac{5}{8}.x=\frac{3}{5}+\frac{7}{2}\\\frac{5}{4}.x+\frac{5}{8}.x=\frac{-3}{5}+\frac{7}{2}\end{array}\right.\)
=> \(\left[\begin{array}{nghiempt}\frac{5}{8}.x=\frac{41}{10}\\\frac{15}{8}.x=\frac{29}{10}\end{array}\right.\)
=> \(\left[\begin{array}{nghiempt}x=\frac{164}{25}\\x=\frac{116}{75}\end{array}\right.\)
Vậy x=\(\frac{164}{25}\) hoặc x=\(\frac{116}{75}\)
\(\frac{x+1}{2008}\)=\(\frac{502}{x+1}\)
=>(x+1)2=502.2008=1008016
=>(x+1)=1004 => x=1004-1=1003
Vậy x=1003
a, 2019 x (2 x 5)
= 2019 x 10
= 20 190
b, (5 x 2) x (8 x 125) x 9
= 10 x 1000 x 9
= 90 000
c, (4 x 25) x 2019
= 100 x 2019
= 201 900
d, (50 x 2) x (125 x 8) x 202
= 100 x 1000 x 202
= 20 200 000
a) 2019 x 2 x 5
= (2 x 5) x 2019
= 10 x 2019
= 20190b) 5 x 8 x 9 x 2 x 125
= (5 x 2) x (125 x 8) x 9
= 10 x 1000 x 9
= 10000 x 9
= 90000
c) 4 x 2019 x 25
= (4 x 25) x 2019
= 100 x 2019
= 201900
d) 50 x 125 x 2 x 8 x 202
= (50 x 2) x (125 x 8) x 202
= 100 x 1000 x 202
= 100000 x 202
= 20200000
2 x (X-8) = 50
X-8 = 50 : 2
X-8 = 25
X = 25 + 8
X = 33
vậy X = 33
2 x X -8 = 50
X-8 = 50 : 2
X-8 = 25
X = 25 + 8
X = 33
vậy X = 33
học tốt!!#