bài 3 Tìm x, biết
a) 13/20+x= 11/15 b) x+ 7/12= -5/6 c) 4/7x= 9/8-0,125 d) 5,5x = 13/15
e) x : 2/3= 13/15 f) -1/2: (x-1/3) = -3/4.
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a.-1,75-(-\(\dfrac{1}{9}\)-2\(\dfrac{1}{8}\))
-1,75-\(\dfrac{1}{9}+\dfrac{17}{8}\)
\(-\dfrac{7}{4}-\dfrac{1}{9}+\dfrac{17}{8}\)
\(\dfrac{-126}{72}-\dfrac{8}{72}+\dfrac{153}{72}\)
=\(\dfrac{19}{72}\)
b.\(\dfrac{-1}{12}-\left(2\dfrac{5}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{-1}{12}-\left(\dfrac{21}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{-1}{12}-\dfrac{21}{8}+\dfrac{1}{3}\)
\(\dfrac{-2}{24}-\dfrac{63}{24}+\dfrac{64}{24}\)
=\(\dfrac{-1}{24}\)
1:
a: \(=\dfrac{-4}{7}+\dfrac{4}{7}+\dfrac{3}{7}-\dfrac{23}{34}-\dfrac{4}{5}=\dfrac{3}{7}-\dfrac{23}{34}-\dfrac{4}{5}=-\dfrac{1247}{1190}\)
b:
Sửa đề: \(\dfrac{-5}{13}+\dfrac{4}{19}+\dfrac{-8}{13}+\dfrac{15}{19}+\dfrac{45}{6}\)
\(=\dfrac{-5}{13}-\dfrac{8}{13}+\dfrac{4}{19}+\dfrac{15}{19}+\dfrac{45}{6}=\dfrac{9}{2}\)
a; - \(\dfrac{10}{13}\) + \(\dfrac{5}{17}\) - \(\dfrac{3}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{11}{20}\)
= - (\(\dfrac{10}{13}\) + \(\dfrac{3}{13}\)) + (\(\dfrac{5}{17}\) + \(\dfrac{12}{17}\)) - \(\dfrac{11}{20}\)
= - 1 + 1 - \(\dfrac{11}{20}\)
= 0 - \(\dfrac{11}{20}\)
= - \(\dfrac{11}{20}\)
b; \(\dfrac{3}{4}\) + \(\dfrac{-5}{6}\) - \(\dfrac{11}{-12}\)
= \(\dfrac{9}{12}\) - \(\dfrac{10}{12}\) + \(\dfrac{11}{12}\)
= \(\dfrac{10}{12}\)
= \(\dfrac{5}{6}\)
c; [13.\(\dfrac{4}{9}\) + 2.\(\dfrac{1}{9}\)] - 3.\(\dfrac{4}{9}\)
= [\(\dfrac{52}{9}\) + \(\dfrac{2}{9}\)] - \(\dfrac{4}{3}\)
= \(\dfrac{54}{9}\) - \(\dfrac{4}{3}\)
= \(\dfrac{14}{3}\)
2:
a: x=2,4-0,4=2
b: =>2x=-1,5+0,8=-0,7
=>x=-0,35
c: =>x-16=-15
=>x=1
\(a,\frac{13}{20}+x=\frac{11}{15}\)
\(x=\frac{11}{15}-\frac{13}{20}\)
\(x=\frac{1}{12}\)
\(b,x+\frac{7}{12}=-\frac{5}{6}\)
\(x=-\frac{5}{6}-\frac{7}{12}\)
\(x=-\frac{17}{12}\)
\(c,\frac{4}{7}x=\frac{9}{8}-0,125\)
\(\frac{4}{7}x=1\)
\(x=1\div\frac{4}{7}\)
\(x=\frac{7}{4}\)
\(\left(d\right)5,5x=\frac{13}{15}\)
\(\frac{11}{2}x=\frac{13}{15}\)
\(x=\frac{13}{15}\div\frac{11}{2}\)
\(x=\frac{26}{165}\)
\(e,x\div\frac{2}{3}=\frac{13}{15}\)
\(x=\frac{2}{3}\times\frac{13}{15}\)
\(x=\frac{26}{45}\)
\(f,-\frac{1}{2}\div\left(x-\frac{1}{3}\right)=-\frac{3}{4}\)
\(x-\frac{1}{3}=-\frac{1}{2}\div-\frac{3}{4}\)
\(x-\frac{1}{3}=\frac{2}{3}\)
\(x=\frac{1}{3}+\frac{2}{3}\)
\(x=1\)